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tensa zangetsu [6.8K]
3 years ago
8

Zero, a hypothetical planet, has a mass of 5.8 x 1023 kg, a radius of 2.7 x 106 m, and no atmosphere. a 10 kg space probe is to

be launched vertically from its surface. (a) if the probe is launched with an initial kinetic energy of 5.0 x 107 j, what will be its kinetic energy when it is 4.0 x 106 m from the center of zero? (b) if the probe is to achieve a maximum distance of 8.0 x 106 m from the center of zero, with what initial kinetic energy must it be launched from the surface of zero?
Physics
1 answer:
Tom [10]3 years ago
5 0
To answer these questions just use the equations for potential energy using the mass and heights described. the potential energy at the prescribed heights = the initial kinetic energy required to reach that height.

Make sure you calculate the force of gravity on the surface using the radius of the planet.
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The diameter of Earth (to two significant figures) is 7900 miles. Calculate its circumference.
Bess [88]

Answer:

The circumference of the Earth is 24818.58 miles

Explanation:

Analysis conceptual : The formula of the circumference is the following:

L= π*D Formula (1)

Where:

L : is the length of the circumference in miles (mi)

π : is the constant

D : is the diameter of the circumference in miles (mi)

Known data

π = 3.1416

D= 7900 miles:  Diameter of the Earth

Problem development

We apply the formula 1 to calculate the circumference of the Earth  (L):

L= π*7900 miles

L= 24818.58 miles

8 0
3 years ago
Represent 7468 N with SI units having an appropriate prefix. Express your answer to four significant figures and include the app
Musya8 [376]

Answer:

7.468 kN

Explanation:

Here the force is given in Newton

Some of the prefixes of the SI units are

kilo = 10³

Mega = 10⁶

Giga = 10⁹

Tera = 10¹²

The number is 7468.0

Here, the only solution where the number of significant figures is kilo. If any other prefix is chosen then the significant figures will increase.

1 kilonewton = 1000 Newton

1\ Newton=\frac{1}{1000}\ kilonewton

\\\Rightarrow 7468\ Newton=\frac{7468}{1000}\ kilonewton\\ =7.468\ kilonewton

So, 7468 N = 7.468 kN

7 0
3 years ago
Which of the following devices is associated with the reception of radio signals?
ki77a [65]
What are the "following" devices ? ?
I think they're a list of choices that you have but aren't sharing.

A few devices associated with the reception of various types of
radio signals include the resonant tank, the local oscillator, the
mixer, the detector, the coherer, the discriminator, the parabolic
reflector, the lecher wires, the audio transducer, the demultiplexer,
and ... my personal guess ... the 'antenna' or 'aerial'.
6 0
3 years ago
Read 2 more answers
What parts of an atom determines which element it is?
uysha [10]

Explanation:

The protons determines the atomic number which helps in identifying an atom of an element

4 0
3 years ago
Read 2 more answers
How many significant digits should the answer to the following problem have? (2.49303 g) * (2.59 g) / (7.492 g) =
Feliz [49]

The number of significant digits to the answer of the following problem is four.

<h3>What are the significant digits?</h3>

The number of digits rounded to the approximate integer values are called the significant digits.

The following problem is

(2.49303 g) * (2.59 g) / (7.492 g) =

On solving we get

= 0.86184566204

The answer is approximated to  0.86185

Thus, the significant digits must be four.

Learn more about significant digits.

brainly.com/question/1658998

#SPJ1

6 0
2 years ago
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