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tensa zangetsu [6.8K]
3 years ago
8

Zero, a hypothetical planet, has a mass of 5.8 x 1023 kg, a radius of 2.7 x 106 m, and no atmosphere. a 10 kg space probe is to

be launched vertically from its surface. (a) if the probe is launched with an initial kinetic energy of 5.0 x 107 j, what will be its kinetic energy when it is 4.0 x 106 m from the center of zero? (b) if the probe is to achieve a maximum distance of 8.0 x 106 m from the center of zero, with what initial kinetic energy must it be launched from the surface of zero?
Physics
1 answer:
Tom [10]3 years ago
5 0
To answer these questions just use the equations for potential energy using the mass and heights described. the potential energy at the prescribed heights = the initial kinetic energy required to reach that height.

Make sure you calculate the force of gravity on the surface using the radius of the planet.
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What is the apparent weight of this same object at Neptune's equator? (Note that Neptune's "surface" is gaseous, not solid, so i
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A spaceship accelerates uniformly for 1220km how much time is needed for the spaceship to increase its speed from 11.1km/s to 11
snow_lady [41]

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s is 107 s

<h3>Data obtained from the question</h3>

The following data were obtained from the question given above:

  • Initial velocity (u) = 11.1 Km/s
  • Final velocity (v) = 11.7 Km/s
  • Distance (s) = 1220 Km
  • Time (t) =?

<h3>How to determine the time</h3>

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s can be obtained as illustrated below:

s = (u + v)t / 2

Cross multiply

(u + v)t = 2s

Divide both sides by (u + v)

t = 2s / (u + v)t

t = (2 × 1220) / (11.1 + 11.7)

t = 2440 / 22.8

t = 107 s

Thus, the time taken for the spaceship to change its speed is 107 s

Learn more about speed:

brainly.com/question/680492

Learn more about velocity:

brainly.com/question/3411682

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A hydrogen bomb has a diameter of about 10nm express this in meters
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1 Nautical metre=1852 metres
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