1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tensa zangetsu [6.8K]
3 years ago
8

Zero, a hypothetical planet, has a mass of 5.8 x 1023 kg, a radius of 2.7 x 106 m, and no atmosphere. a 10 kg space probe is to

be launched vertically from its surface. (a) if the probe is launched with an initial kinetic energy of 5.0 x 107 j, what will be its kinetic energy when it is 4.0 x 106 m from the center of zero? (b) if the probe is to achieve a maximum distance of 8.0 x 106 m from the center of zero, with what initial kinetic energy must it be launched from the surface of zero?
Physics
1 answer:
Tom [10]3 years ago
5 0
To answer these questions just use the equations for potential energy using the mass and heights described. the potential energy at the prescribed heights = the initial kinetic energy required to reach that height.

Make sure you calculate the force of gravity on the surface using the radius of the planet.
You might be interested in
The free-fall acceleration at the surface of planet 1 is 22 m/s^2. The radius and the mass of planet 2 are twice those of planet
algol13

Answer:

g₂ = 11 m/s²

Explanation:

The value of free-fall acceleration on the surface of a planet is given by the following formula:

g = \frac{Gm}{r^2}

where,

g = free-fall acceleration

G = Universal Gravitational Constant

m = mass of the planet

r = radius of planet

FOR PLANET 1:

g_1 = \frac{Gm_1}{r_1^2}\\\\\frac{Gm_1}{r_1^2} = 22 m/s^2 --------------------- equation (1)

FOR PLANET 2:

g_2 = \frac{Gm_2}{r_2^2}\\\\g_2 = \frac{G(2m_1)}{(2r_1)^2}\\\\g_2 = \frac{1}{2}\frac{Gm_1}{r_1^2}\\\\

using equation (1):

g_2 = \frac{g_1}{2}\\\\g_2 = \frac{22\ m/s^2}{2}

<u>g₂ = 11 m/s²</u>

8 0
2 years ago
A student drops a rubber ball onto a surface. Assume that this is a closed system. The ball bounces, but each successive bounce
spayn [35]
I would say D.) The ball bounces many times suggesting the energy is used up efficiently
5 0
2 years ago
Read 2 more answers
1. An object is traveling at a constant velocity of 30 m/s when it experiences a constant
Yanka [14]

Answer:use

Explanation:google

7 0
3 years ago
1. Indicate whether these objects or atoms are positively,<br> negatively or neutrally charged.
vovangra [49]

Answer:

Neutrally charged!!!!!!!!!!!!!!!!!!!!!

Explanation:

6 0
3 years ago
A pendulum has 711 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
Anika [276]
According to law of conservation of energy, 
<span>Energy can neither be constructed nor be destroyed but can be transformed from one form to another.
</span>
<span>At the highest point of the pendulum(point b), pendulum is associated with potential energy only and no kinetic energy.
</span><span>Therefore total energy at point b = potential energy = 711 J.... i
</span>
<span>At the bottom most point(point a), pendulum is associated only with kinetic energy and no potential energy.
</span>Therefore total energy at point a = kinetic energy ---- ii
<span>From i and ii,
</span>Kinetic energy = potential energy = 711 J.(Conserving energy)

Hence kinetic energy at the bottom most point is 711 J.
Hope this helps!!

7 0
3 years ago
Other questions:
  • A capacitor stores 7.6 × 10–11 C when the electric potential difference between the plates is 5.8 V. What is the electric potent
    8·1 answer
  • Two​ pulleys, one with radius 2 inches and one with radius 9 inches​, are connected by a belt. If the 2-inch pulley is caused to
    5·1 answer
  • A box is sitting on the ground and weighs 100 kg and the coefficient of friction is 0.23. Is it easier to push by applying the f
    7·1 answer
  • What happens to the air temperature of a descending mass of air?
    15·1 answer
  • How do stars, like our sun, release energy? Is it fission or fusion?
    13·2 answers
  • The speed of sound through oxygen at 0°C is 316 meters per second. The speed of sound through solid copper is 5,010 meters per s
    6·2 answers
  • Suppose the tank is open to the atmosphere instead of being closed. how does the pressure vary along
    13·1 answer
  • The shaded boxes contain the first half of four statements. The unshaded boxes
    15·1 answer
  • Ned is learning about cells in science class. He drew a picture to model a cell. What can he show with his cell drawing?
    12·2 answers
  • OBJECTI
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!