This graph describes the motion of a sky diver that jumped from an airplane. The skydiver is MOST LIKELY ?

Physics

1 answer:

tensa zangetsu [6.8K]3 years ago

3 0

Answer:

A) being influenced by equal amounts of gravity and air resistance.

Explanation:

B) slowing down because of an unbalanced force of air resistance.

False - if it was slowing down, then the velocity would go down.

D) on the ground and is not falling anymore.

False - This would be mistaken as the answer but it is not because if the person is not falling anymore the horizontal line should be at the x-axis, meaning that there is no more velocity.

C) accelerating because of an unbalanced force of gravity.

False - The line would otherwise be going up or down.

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An object is hanging from a rope. When it is held in air the tension in the rope is 8.86 N, and when it is submerged in water th

SSSSS [86.1K]

Answer:

8684.2 kg/m³

Explanation:

Tension in the rope as a result of the weight = 8.86 N

Tension in the rope when submerge in water = 7.84

upthrust = 8.86 - 7.84 =1.02 N = mass of water displaced × acceleration due to gravity

Mass of water displaced = 1.02 / 9.81 = 0.104 kg

density of water = mass of water / volume of water

make volume subject of the formula

volume of water displaced = mass / density ( 1000) = 0.104 / 1000 = 0.000104 m³

volume of the object = volume of water displaced

density of the object = mass of the object / volume of the object = (8.86 / 9.81) / 0.000104 = 0.9032 / 0.000104 = 8684.2 kg/m³

8 0

3 years ago

How many bits can be stored on a 20 GB hard disk? (Hint: 1GB= 1,073,741,824 bytes; 1 byte=8 bits.)

Aloiza [94]

<span>17,179,8691,840</span> should be the correct answer

hope this helps

5 0

4 years ago

Why does a batsman striking a cricket ball follow through?

Over [174]

A good follow-through maintains flow in the motion. It is to hit 'smooth', rather than to hit 'hard'. It is to maintain a certain 'looseness' in the swing, rather than 'tension' or 'over-hitting' the ball with too much power.

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3 years ago

If the retina is 1.7 cm from the lens in the eye, how large is the image on the retina of a person of height 1.5 m standing 9.0

sineoko [7]

Answer:

The image height is 0.00283 m or 0.283 cm and is inverted due to the negative sign

Explanation:

u = Object distance = 9 m

v = Image distance = 1.7 cm (as the image is forming on the retina)

$h_u$ = Object height = 1.5 m