Area of a trapezoid= (big base+small base)/2 x height
A=(67+54)/2 x 18
A=60.5 x 18
A=1089
Hope this helps :)
Answer:
<h2>BELOW </h2>
Step-by-step explanation:
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Answer:
Step-by-step explanation:
The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.
Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.
To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a , creating right triangles and .
The Pythagorean Theorem states that the following is true for any right triangle:
, where is the hypotenuse, or the longest side, of the triangle
Thus, we have:
Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.
What we know:
Thus, the perimeter of the quadrilateral PTOS is equal to
Answer:
780$
Step-by-step explanation:
f(8) = 500 + 35x8
500 + 280
To start, set up and equation using what you know.
(5/6) / (a/b) = (1/4)
Then, you need to isolate a/b. To do this multiply both sides by a/b and then divide by 1/4
5/6 = (a/b) (1/4)
(5/6) / (1/4) = (a/b)
Next, simplify the left side. To do this, take the inverse of 1/4 (which is 4) and multiply by 5/6 (this is also know as 'flip the second guy and multiply').
(5/6) • 4 = a/b
20/6 = a/b
Lastly, simplify to get the final answer.
10/3 = a/b