What is the percent composition of hydrogen in vinegar (CH3COOH)?

Chemistry

1 answer:

barxatty [35]3 years ago

6 0

Answer:

%H = 6.72 %

Explanation:

Percent composition of an element is the total mass of that element divided by the molecular mass of compound (or molecular mass) of which it is present in.

So,

Percent composition of Hydrogen will be given as,

%H = Total mass of H / Molecular Mass of Acetic Acid × 100

So,

Total Mass of H = 1.01 × 4 = 4.04 g

Molecular Mass of Acetic acid = 60.052 g/mol

Putting values in above formula,

%H = 4.04 g/mol ÷ 60.052 g/mol × 100

%H = 6.72 %

You might be interested in

Need help <br>1/6 + 1/8 =

pogonyaev

1/6 + 1/8 = 7/24

≅ 0.2916667

6 0

3 years ago

What is the maximum number of electrons that an atomic orbital can contain?<br> 2<br> 1<br> 8<br> 32

zavuch27 [327]

Answer:

Explanation:

google

4 0

3 years ago

1. Sodium hydroxide reacts with carbon dioxide according to the equation: 2NaOH(s) + CO2(g) →

Leno4ka [110]

The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH

<h3>What is Limiting reagent ?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

Given chemical equation in balanced form ;

2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).

According to the Chemical equation ;

The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH

If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.

But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.
6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react

As 80 g NaOH produces 106 g of Na₂CO₃.

Therefore 5 g NaoH will produce ;

106 / 80 x 5 = 6.625 g