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xxMikexx [17]
1 year ago
14

Please help me with this thank you!

Chemistry
1 answer:
ludmilkaskok [199]1 year ago
5 0

Answer:

1. B

2. C

3. A

4. E

5. D

6. A, B

7. C, E

8. D

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What is the answer? show proof I will report you if you answer for the points​
IceJOKER [234]

Answer:

A

Explanation:

carbon dioxide is released in cellular respiration

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2 years ago
Jumping on a cemented floor is more pain full than a sandy flour,why​
Anvisha [2.4K]

Answer:

Is soft

Explanation:

because concrete is hard ash so t hink flour would be safer

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3 years ago
What is the electron configuration for a neutral atom of fluorine.
zavuch27 [327]

Answer and Explanation: The full ground-state electron configuration for a fluorine atom is 1s2, 2s2, 2p5. We determine this by first identifying the number of electrons in a fluorine atom. If the atom is neutral, it will have nine electrons to match the nine protons int he fluorine nucleus

6 0
2 years ago
Read 2 more answers
Which of the following is an example of ionization of an acid?
Amiraneli [1.4K]

Answer:

NH3(g) + H2O(1) → NH4+(aq) + OH (aq)

HF(aq) + H2O(1) → H3O+(aq) + F (aq)

Explanation:

Acid-base reactions are chemical reactions involving acids and bases. Acids tend to ionize/dissociate in water, a property which determines their strength. Ionization of an acid refers to the acid losing its hydrogen ion (H+) in water solution. An acid ionizes or dissociates to form a conjugate base.

A strong acid is so because it ionizes completely in water i.e. loses all its hydrogen ion (H+) while a weak acid partially ionizes in water.

In the chemical reactions;

1) NH3(g) + H2O(1) → NH4+(aq) + OH (aq)

H20 loses its hydrogen ion (H+) in this reaction to form an anion (OH-). Hence, water (H20) is an acid in this case which ionizes to form a conjugate base (OH-). This is an example of ionization of acid.

2) HF(aq) + H2O(1) → H3O+(aq) + F (aq)

Hydrogen fluoride (HF) loses its hydrogen ion (H+) in the presence of water to form anion (F-). The HF is the acid while F- is it's conjugate base. Thus, an example of ionization of acid

4 0
3 years ago
At 330 K the vapor pressure of pure n-pentane is 1.92 atm and the vapor pressure of pure n-octane is 0.07 atm. If 330K is the no
AleksAgata [21]

Answer: mole fractions are

For n-pentane = 0.965

For n-octane = 0.035

Explanation: pressure exerted by each gas is,

n-pentane = 1.92atm

n-octane = 0.07atm

Total pressure exerted = 1.92 + 0.07

= 1.99atm.

Recall that the partial pressure exerted by each gas is the product of its mole fraction and the total pressure, that is,

Pres. n-pentane = n x pressure(total)

1.92 = n x 1.99

n = 1.92/1.99 = 0.965 for n-pentane

For n-octane,

n = 1 - 0.965 = 0.035 for n-octane.

7 0
3 years ago
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