Answer:
The size of the electric current is 154.74 A.
Explanation:
It is assumed that,
Charge, q = 93 C
Time, ![t=601\ ms=601\times 10^{-3}\ s](https://tex.z-dn.net/?f=t%3D601%5C%20ms%3D601%5Ctimes%2010%5E%7B-3%7D%5C%20s)
We need to find the size of the electric current. It is equal to the electric charge per unit time. It is given by :
![I=\dfrac{q}{t}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7Bq%7D%7Bt%7D)
![I=\dfrac{93\ C}{601\times 10^{-3}\ s}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B93%5C%20C%7D%7B601%5Ctimes%2010%5E%7B-3%7D%5C%20s%7D)
I = 154.74 A
So, the size of the electric current is 154.74 A. Hence, this is the required solution.
Answer: 1. The law of consevation of energy sates that energy can neither be created nor destroyed. It can only be transformed or transfered from one form to another. The law of conservation of energy is found everywhere for example, Water falls from the sky, converting potential energy to kinetic energy.
2. Different forms of energy are related because energy cannot be created or destroyed. they can all be transformed into from one form to another.
Explanation:
Answer:
its most definitely c. trust me
Explanation:
The magnitude of the force that the beam exerts on the hi.nge will be,261.12N.
To find the answer, we need to know about the tension.
<h3>How to find the magnitude of the force that the beam exerts on the hi.nge?</h3>
- Let's draw the free body diagram of the system using the given data.
- From the diagram, we have to find the magnitude of the force that the beam exerts on the hi.nge.
- For that, it is given that the horizontal component of force is equal to the 86.62N, which is same as that of the horizontal component of normal reaction that exerts by the beam on the hi.nge.
![N_x=86.62N](https://tex.z-dn.net/?f=N_x%3D86.62N)
- We have to find the vertical component of normal reaction that exerts by the beam on the hi.nge. For this, we have to equate the total force in the vertical direction.
![N_y=F_V=mg-Tsin59\\](https://tex.z-dn.net/?f=N_y%3DF_V%3Dmg-Tsin59%5C%5C)
- To find Ny, we need to find the tension T.
- For this, we can equate the net horizontal force.
![F_H=N_x=Tcos59\\\\T=\frac{F_H}{cos59} =\frac{86.62}{0.51}= 169.84N](https://tex.z-dn.net/?f=F_H%3DN_x%3DTcos59%5C%5C%5C%5CT%3D%5Cfrac%7BF_H%7D%7Bcos59%7D%20%3D%5Cfrac%7B86.62%7D%7B0.51%7D%3D%20169.84N)
- Thus, the vertical component of normal reaction that exerts by the beam on the hi.nge become,
![N_y= (40*9.8)-(169.8*sin59)=246.4N](https://tex.z-dn.net/?f=N_y%3D%20%2840%2A9.8%29-%28169.8%2Asin59%29%3D246.4N)
- Thus, the magnitude of the force that the beam exerts on the hi.nge will be,
![N=\sqrt{N_x^2+N_y^2} =\sqrt{(86.62)^2+(246.4)^2}=261.12N](https://tex.z-dn.net/?f=N%3D%5Csqrt%7BN_x%5E2%2BN_y%5E2%7D%20%3D%5Csqrt%7B%2886.62%29%5E2%2B%28246.4%29%5E2%7D%3D261.12N)
Thus, we can conclude that, the magnitude of the force that the beam exerts on the hi.nge is 261.12N.
Learn more about the tension here:
brainly.com/question/28106871
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The ratio of (new volume / old volume) is the same as the ratio of (new temperature / old temp).
Just remember that you have to use the ABSOLUTE temperatures.
An absolute temperature is (Celsius + 273).