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aksik [14]
4 years ago
13

The planet closest to the sun that has a dense iron core and no moons would most likely be?. A. Mars. B. Mercury. C. Earth. D. V

enus
Physics
1 answer:
Oduvanchick [21]4 years ago
3 0
The planet closest to the sun that has a dense iron core and no moons is : B. mercury
From the options above, only mercury and venus are the one that doesn't have moons. Between the two, mercury is the one that has a dense iron core

hope this helps

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Two cars enter the Florida Turnpike at Commercial Boulevard at 8:00 AM, each heading for Wildwood. One car’s average speed is 10
olganol [36]

Answer:

The average speed of the cars is 50mph

Explanation:

Option C

4 0
3 years ago
A book that weighs 16N is on top of a shelf that is 3m high. What is the work required to
DENIUS [597]

48J

Explanation:

Given parameters:

Weight of the book = 16N

Height of the shelf = 3m

Unknown:

Work done to raise the book = ?

Solution:

Work done is defined as the product of force and distance. The force here is the weight of the book which signifies that it was carried in the vicinity of gravitational force.

   Work done = Force x  distance = weight x distance

Weight is a type of force;

  Input the parameters;

     Work done = 16 x 3 = 48J

The unit of workdone is in Joules

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

8 0
3 years ago
Which sentence best describes a role of gravity in the formation of the
enyata [817]

Answer:

I think it's option D

Explanation:

I think it's option D but not so sure

8 0
3 years ago
Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.0
Tema [17]

Answer:

841.5 Hz

Explanation:

Given

y = 50 cm = 0.5 m

d = 5.00 m

L = 12.0 m away from the wall

v = speed of sound = 343 m/s

The image of the scenario is presented in the attached image.

When destructive interference is being experienced from 50 cm (0.5 m) parallel to the wall, the path difference between the distance of the two speakers from the observer is equal to half of the wavelength of the wave.

Let the distance from speaker one to the observer's new position be d₁

And the distance from the speaker two to the observer's new position be d₂

(λ/2) = |d₁ - d₂|

d₁ = √(12² + 3²) = 12.3693 m

d₂ = √(12² + 2²) = 12.1655 m

|d₁ - d₂| = 0.2038 m

(λ/2) = |d₁ - d₂| = 0.2038

λ = 0.4076 m

For waves, the velocity (v), frequency (f) and wavelength (λ) are related thus

v = fλ

f = (v/λ) = (343/0.4076) = 841.5 Hz

Hope this Helps!!!

7 0
4 years ago
Read 2 more answers
A cricket ball of mass 800g has momentum of 20kg m/s , calculate velocity of ball?
larisa86 [58]

P=MV

V=P/M

20/800

0.025

8 0
4 years ago
Read 2 more answers
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