Answer:
1. C4H8 + 6O2 -----> 4CO2 + 4H20
2. 3836.77 kcal
Explanation:
1. Balanced equation for the complete combustion of cyclobutane:
C4H8 + 6O2 -----> 4CO2 + 4H20
2. Heat of combustion of cyclobutane = 650.3 kcal/mol
Molecular weight of cyclobutane, C4H8 = 56.1 g/mol
Mole of C4H8 : mass of cyclobutane/Molecular weight of cyclobutane
Mole of C4H8 = 331/56.1 = 5.9 mol
Energy released during combustion = 5.9 mol × 650.3 kcal/mol = 3836.77kcal
Therefore the energythat is released during the complete combustion of 331 grams of cyclobutane is 3836.77kcal
Answer:
A HBr
this is hydrogen acid (HBr) but KNO3 is a crystalline salt,MgCl2 and H2O are neutral
Answer:
Mass of CO₂ produced = 5.72 g
Explanation:
Given data:
Mass of methane = 2.34 g
Mass of oxygen = 8.32 g
Mass of CO₂ produced = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of methane:
Number of moles = mass/molar mass
Number of moles = 2.34 g/ 16 g/mol
Number of moles = 0.146 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 8.32 g/ 32 g/mol
Number of moles = 0.26 mol
Now we will compare the moles of carbon dioxide with oxygen and methane.
CH₄ : CO₂
1 : 1
0.146 : 0.146
O₂ : CO₂
2 : 1
0.26 : 1/2×0.26 = 0.13 mol
Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 0.13 mol × 44 g/mol
Mass = 5.72 g
they both describe atoms as being made up of positive and negative matter
