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3 years ago

Calculate the number of moles of O2 gas held in a sealed 2.00 L tank at 3.50 atm and 25 ℃.

Chemistry

1 answer:

Leviafan [203]3 years ago

6 0

Answer:

$n=0.286mol$

Explanation:

Hello,

In this case, we consider oxygen as an ideal gas, for that reason, we use yhe ideal gas equation to compute the moles based on:

$PV=nRT\\\\n=\frac{PV}{RT}$

Hence, at 3.50 atm and 25 °C for a volume of 2.00 L we compute the moles considering absolute temperature in Kelvins:

$n=\frac{3.50atm*2.00L}{0.082\frac{atm*L}{mol*K}(25+273)K} \\\\n=0.286mol$

Best regards.

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PV=nRT
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3 years ago

A 2.00 L sample of gas at 35C is to be heated at constant pressure until it reaches a volume of 5.25 L. To what Kelvin temperat

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Answer:

When the volume increased from 2.00 to 5.25L the new temperature is 808.9 K ( =535.75 °C)

Explanation:

Step 1: Data given

The initial volume of the sample = 2.00 L

The initial temperature = 35 °C = 308 K

The increased volume = 5.25 L

Pressure = constant

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒ with V1 = the initial volume = 2.00 L

⇒ with T1 = the initial volume = 308 K

⇒ with V2 = the new volume = 5.25 L

⇒ with T2 = the new temperature

2.00 / 308 = 5.25 / T2

0.00649 = 5.25/T2

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A chemist dissolves 716.mg of pure potassium hydroxide in enough water to make up 130.mL of solution. Calculate the pH of the so

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<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

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Molar mass of KOH = 56 g/mol

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Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{0.716\times 1000}{56g/mol\times 130}\\\\\text{Molarity of solution}=0.098M$

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To calculate hydroxide ion concentration of the solution, we use the equation:

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We are given:

[tex[[OH^-]=0.098M[/tex]

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