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arsen [322]
3 years ago
14

A flask contains Ne at 542 mmhg together with At at 234 mmHg. What will the total pressure be?

Chemistry
1 answer:
sineoko [7]3 years ago
3 0

Answer:

The total pressure will be 1, 021 atm

Explanation:

We apply Dalton's law, where for a gas mixture the total pressure is the sum of the partial pressures of each gas that makes up that mixture. The unit of pressure is converted into atm:

760mmHg----1 atm

542mmHg----x=(542mmHgx 1 atm)/760mmHg=0,713 atm

234mmHg----x=(234mmHgx 1 atm)/760mmHg=0,308 atm

Pt=P Ne + P At= 0,713 atm + 0,308 atm= <em>1, 021 atm</em>

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A sample of gas has a volume of 2.36 L at a temperature of 53.00 °C. The gas sample is heated to a temperature of 139.00 °C (ass
Liono4ka [1.6K]

Answer:

The volume increases because the temperature increases and is 2.98L

Explanation:

Charles's law states that the volume of a gas is directely proportional to its temperature. That means if a gas is heated, its volume will increase and vice versa. The equation is:

V₁/T₁ = V₂/T₂

<em>Where V is volume and T is absolute temperature of 1, initial state, and 2, final state of the gas.</em>

In the problem, the gas is heated, from 53.00°C (53.00 + 273.15 = 326.15K) to 139.00°C (139.00 + 273.15 = 412.15K).

Replacing in the Charles's law equation:

2.36L / 326.15K= V₂/412.15K

<h3>2.98L = V₂</h3>

<em />

5 0
3 years ago
Which of the following sets of empirícal formula, molar mass, and molecular formula is correct?
skad [1K]

<em>Answer:</em>

  • The option C is correct.
  • CH4N, 90g, C3H12N3.

<em>Explanation:</em>

                    <em>Option C:</em>

  • The molecular formula is C3H12N3.
  • If we take ratio 3:12:3 that will be equal to 1:4:1 so its empirical formula will be CH4N.
  • The molar mass of molecular formula = (12×3) + (1×12) +( 14×3) = 98 g

                <em>Option A :</em>

  • In option A , molecular and empirical formula are both correct but molar mass is not valid. It should be 169 acc. to molecular formula.

              <em>Option B:</em>

  • In option B, molecular formual is not valid.
  • It should be as C6H16O2
4 0
3 years ago
which method would be best for separating the compounds of a mixture that is made from two diffrent liquids
kobusy [5.1K]

Answer:

fractional distillation since ot depends on the different liquids to have different boiling points

5 0
3 years ago
When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H
Taya2010 [7]

Answer:

- Empirical:

C_3H_7

- Molecular:

C_6H_{14}

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC

Moreover, the moles of hydrogen:

n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

C_3H_7

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

C_6H_{14}

Which is hexane.

Best regards.

6 0
3 years ago
PLEASE HELP WITH TRUE OR FALSE QUESTIONS!!!!!
Elodia [21]
First one is true second one is False
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