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3 years ago

15

A cannon Is pointed Upward 30 degrees and fires a cannonball with a speed of 100m/sec what is the component of the cannon balls

velocity parallel to the groud

1 answer:

Kamila [148]3 years ago

6 0

Answer:

86.6 m/s

Explanation:

vₓ = v cos θ

vₓ = 100 m/s cos 30°

vₓ = 86.6 m/s

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Is the following true or false?

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True, recycling allows products to be reused which saves alot the natural resources that are used.

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Paul and Ivan are riding a tandem bike together. They’re moving at a speed of 5 meters/second. Paul and Ivan each have a mass of

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Well they could go down a hill to gain more kinetic energy.

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A 300 g glass thermometer initially at 23 ◦C is put into 236 cm3 of hot water at 87 ◦C. Find the final temperature of the thermo

DIA [1.3K]

Answer:

$74^{\circ} C$

Explanation:

We are given that

Mass of glass, $m=300 g$

$T_1=23^{\circ}$

Volume, $V=236cm^3$

Mass of water= $density\times volume=1\times 236=236 g$

Density of water= $1g/cm^3$

Temperature of hot water, $T=87^{\circ}$

Specific heat of glass, $C_g=0.2cal/g^{\circ}C$

Specific heat of water, $C_w=1 cal/g^{\circ}C$

$Q_{glass}=m_gC_g(T_f-T_1)=300\times 0.2(T_f-23)$

$Q_{water}=m_wC_w(T_f-T)=236\times 1(T_f-87)$

$Q_{glass}+Q_{water}=0$

$300\times 0.2(T_f-23)+236\times 1(T_f-87)$

$60T_f-1380+236T_f-20532=0$

$296T_f=20532+1380=21912$

$T_f=\frac{21912}{296}=74^{\circ} C$

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3 years ago

A student practicing for a cross country meet runs 250 m in 30 s. What is the average speed

Kaylis [27]

Answer:8.3m/sec 30 sec,

Explanation:

A student practicing for a track meet, ran 250 m in 30 sec. a. What was her average speed? 250 m = 8.3 m/sec 30 sec.

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2 years ago

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A fixed mass of an ideal gas is heated from 50°C to 80°C (a) at constant volume and (b) at constant pressure. For which case do

soldi70 [24.7K]

Answer:

Specific heat at constant pressure is = 1.005 kJ/kg.K

Specific heat at constant volume is = 0.718 kJ/kg.K

Explanation:

given data

temperature T1 = 50°C

temperature T2 = 80°C

solution

we know energy require to heat the air is express as

for constant pressure and volume

Q = m × c × ΔT ........................1

here m is mass of the gas and c is specific heat of the gas and Δ T is change in temperature of the gas

here both Mass and temperature difference is equal and energy required is dependent on specific heat of air.

and here at constant pressure Specific heat is greater than the specific heat at constant volume,

so the amount of heat required to raise the temperature of one unit mass by one degree at constant pressure is

Specific heat at constant pressure is = 1.005 kJ/kg.K

and

Specific heat at constant volume is = 0.718 kJ/kg.K

3 0

3 years ago