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3 years ago

What acceleration did you measure from the video? Does this match the acceleration you calculated in the first step?

Physics

1 answer:

OLEGan [10]3 years ago

6 0

Explanation:

dont know so sorryyyyyyyyy

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The bar ab has a velocity at point a of va = [20,9] m/s and an angular velocity w = 23 rad/s. If the distance between a and b is

DiKsa [7]

speed of point A is given as

$v_a = 20.9 m/s$

$v_a = r*\omega$

here r = distance from the axis

so here we have

$20.9 = r*23$

$r = 0.91 m$

now the distance of point A and B is 0.71 m

while the distance of axis from point A is 0.91 m

so distance of axis from point B will be given as

$r = 0.91 + 0.71 = 1.62 m$

now for the speed of point b is given as

$v = r \omega$

$v = 1.62 * 23$

$v = 37.26 m/s$

so end point B will move with speed 37.26 m/s

8 0

3 years ago

The waves that have shorter wavelengths than visible light are

alekssr [168]

C. ultraviolet rays & D. gamma rays

4 0

3 years ago

Mars’s moon Phobos orbits the planet at a distance of 9380 km from its center, and it takes 7 hours and 39 minutes to complete o

sukhopar [10]

Answer: 0.107

Explanation:

We can solve this problem with Kepler's Third Law of Planetary motion:

$T^{2}=4 \pi^{2} \frac{r^{3}}{G M_{MARS}}$ (1)

Where:

$T=7 h 39 min$ is the orbital period of Phobos around Mars

$G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the Gravitational Constant

$M_{MARS}$ is the mass of Mars

$r=9380 km \frac{1000 m}{1 km}=9,380,000 m$ is the semimajor axis of the orbit Phobos describes around Mars (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)

Well, firstly we have to convert the orbital period to seconds:

$T=7 h 39 min=(7 h \frac{3600 s}{1 h}) + (39 min \frac{60 s}{1 min})=25200 s + 2340 s=27540 s$

Now, we have to find $M_{MARS}$ from (1):

$M_{MARS}=\frac{4 \pi^{2} r^{3}}{G T^{2}}$ (2)

$M_{MARS}=\frac{4 \pi^{2} (9,380,000 m)^{3}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}) (27540 s)^{2}}$ (3)

$M_{MARS}=6.436(10)^{23} kg$ (4) This is the mass of Mars

On the other hand, it is known the mass of the Earth is:

$M_{EARTH}=5.972(10)^{24} kg$ (5)

Then, if we want to know the ratio of Mars’s mass to the mass of the earth, we have to divide $M_{MARS}$ by $M_{EARTH}$ :

$\frac{M_{MARS}}{M_{EARTH}}=\frac{6.436(10)^{23} kg}{5.972(10)^{24} kg}$

Finally:

$\frac{M_{MARS}}{M_{EARTH}}=0.107$

7 0

4 years ago

Lisa can run the 100 m dash in 22 seconds. What is her speed?

horsena [70]

Speed = distance/ time taken

v = d/ t

v 100m / 22s

lisa speed = v = 4.55m⁻²

5 0

3 years ago

The atmospheric pressure is 1 ATM.What does it mean?

ohaa [14]

Answer: the atmospheric pressure is generally expressed in terms of the height of the mercury column.at normal temperature and pressure, the barometric height is 760mm at sea level which is taken as one atmosphere. thus atmospheric pressure is also expressed in a unit atmosphere where 1 atm= 0.76m of hg. 9

3 0

3 years ago