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FromTheMoon [43]
3 years ago
13

What acceleration did you measure from the video? Does this match the acceleration you calculated in the first step?

Physics
1 answer:
OLEGan [10]3 years ago
6 0

Explanation:

dont know so sorryyyyyyyyy

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HELP ME 20 POINTS!!!Assume that the average volume of an adult human body is one-tenth
Agata [3.3K]

Answer:

,Assume that the average volume of an adult human body is one-tenth

cubic meter (0.10 m) and that there are two billion (2.0 x 109)

adults in the world.

a. What would be the total volume of all the adults in the world?

b. Compute the length of one edge of a cubic container that has a

volume equal to the volume of all the adults in the world.

8 0
3 years ago
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A car travels 82 meters do North and 14 seconds the car turns around and travels 44 m due south in four seconds what is the magn
Yakvenalex [24]

Answer:

2.11 m/s

Explanation:

Take north to be positive and south to be negative.

Average velocity = displacement / time

v = (82 m + -44 m) / (14 s + 4 s)

v = 2.11 m/s

The velocity is positive, so it is 2.11 m/s north.  The magnitude of the velocity is 2.11 m/s.

8 0
3 years ago
HURRY PEASE what happens to current when there is a diode on the circuit and why?
kolbaska11 [484]

Answer:

The current can't 'split down the parallel branch, because the diode is reverse biased so is blocking the flow of current. So basically it's acting as an open circuit. Also when the current flows it wouldn't reduce the currents amount flow through the resistor.

Explanation:

6 0
3 years ago
On a day when the temperature reaches 50°F, the temperature in degrees Celsius is: 20°C
anzhelika [568]

Answer:

10°C

Explanation:

To convert °F to °C, we use the formula:

°C =  (°F - 32) * ( 5/9)

So, to convert 50°F to the equivalent  in °C, we can proceed as follows:  

°C = ( 50 - 32 ) * (5/9)  

°C = ( 18 ) *  (5/9), which is, approximately,

°C = 9.999999999... ≈ 10 (5/9 ≈0.555555...)

So, 50°F is equivalent to 10°C.

3 0
3 years ago
The molar enthalpy of fusion for water is 6.008 kj/mol. what quantity of energy is released when 253g of liquid water freezes? (
e-lub [12.9K]
During freezing, energy is released by the mass of water without change in temperature. Such energy will also be required if the same mass of water has to be melted.

Then,

Number of moles = mass/molar mass = 253/18.02 =14.04 moles

Energy released = moles*molar enthalpy of fusion = 14.04*6.008 = 84.35 kJ
6 0
2 years ago
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