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CaHeK987 [17]
3 years ago
10

Which of the following tests uses calipers to assess body composition? A. skinfold test B. sit-and-reach C. arm hang D. curl-up

Please select the best answer from the choices provided. ​
Physics
1 answer:
Stolb23 [73]3 years ago
6 0

Answer:A.skinfold test

Explanation:

i just took the test

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A particle moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.
mrs_skeptik [129]

The particle's acceleration is 5.1 m/s²

<h3>What is Acceleration ?</h3>

Acceleration can be defined as the rate at which velocity is changing. It is a vector quantity and it is measured in m/s²

Given that a particle is moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.72 m/s at t=5.59s

The given parameters are;

  • V1 = 2.35 m/s
  • V2 = - 8.72 m/s
  • T1 = 3.42s
  • T2 = 5.59s

Acceleration a = ΔV ÷ ΔT

a = (2.35 + 8.72) / (5.59 - 3.42)

a = 11.07 / 2.17

a = 5.1 m/s²

Therefore, the particle's acceleration is 5.1 m/s²

Learn more about Acceleration here: brainly.com/question/9069726

#SPJ1

4 0
2 years ago
A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to
jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire  =3.7\ MA

b) Current at the center of the circular coil =2.48\times 10^{5}\ A

c) Current near the center of a solenoid 236.8\ A

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}

\mu=4\pi \times 10^{-7}\ \frac{henry}{m}

Plugging the values,

Conversion 1\times 10^6 A = 1\ MA,and 2cm=\frac{2}{100}=0.02\ m

I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA

⇒Magnetic Field at the center due to circular coil (at center) is given by,B=\frac{\mu\times I (N)}{2(a)}

So I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A

⇒Magnetic field due to the long solenoid,B=\mu\ nI=\mu (\frac{N}{l})I

Then I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A  

So the value of current are  3.7 MA,2.48\times 10^{5} A and 236.8\ A respectively.

8 0
3 years ago
Which type of bone is this <br>covalent bond<br>hydrogen bond <br>ionic bond​
Fynjy0 [20]

Answer:

Explanation:A covalent bond is formed when electrons are shared between non-metal atoms, and the positive nuclei are attracted towards the pair of negative bonded electrons. ... Hence, the hydrogen bond is weaker than ionic and covalent bonds. Example: Water molecules are held to each other by intermolecular forces of attraction.

5 0
3 years ago
The volume of a cylindrical tin can with a top and a bottom is to be 16π cubic inches. If a minimum amount of tin is to be used
sergiy2304 [10]

Answer:

h = 4 in

Explanation:

GIVEN DATA:

volume of tin= 16 \pi

we know that

volume of cylinder is v = \pi r^2  h

so,

16 \pi = \pi r^2 h

16 = r^2 h

r = \sqrt{\frac{16}{h}}

construct formula for surface area

S = 2\pi r^2 +  2\pi rh

S = \frac{2v}{h} + 2 \sqrt{v \pi h}

minimize the function wrt  h

S' = \frac{2v}{h^2} + \sqrt{\frac{v \pi}{h} =  0

solving for h we have

h = [\frac{4 v}{\pi}]^{1/3}

we kow v = 16 \pi   so

h = 4 in

8 0
3 years ago
Pls help me I don’t get it :(
Ksju [112]

Answer:

2nd and 4th

Explanation:

4 0
2 years ago
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