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2 years ago

7

If the results of an experiment disprove a hypothesis, then the a. results should not be reported. b. hypothesis is just a theor

y. c. data must contain errors. d. none of the above

1 answer:

Alina [70]2 years ago

3 0

B.Hypothesis is just a theory.

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Which group has elements with the most diverse set of properties??

TiliK225 [7]

Group 4A

The elements in group 4 show the most diverse set of properties.

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What would happen if an alkali metal was combined with a halogen?explain

RideAnS [48]

All alkail metals react with halogens vigorously to produce salt. The alkali metal would loose an electron to form and ion with the halogen

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3 years ago

Consider the following data:

VikaD [51]

∆H ° rxn =-2855.56 kJ

<h3>Further explanation</h3>

Given

ΔHf CO₂ = -393.5 kJ/mol

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2C2H6(g) + 7O2(g) -> 4CO2(g) + 6H2O(g)

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ΔHrxn=

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2 years ago

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Write the Iconic Bond to Metals

Nutka1998 [239]

<u>Answer:</u> The ionic compound formed is magnesium chloride having formula $MgCl_2$

<u>Explanation:</u>

Ionic compound is defined as the compound which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Magnesium is the 12th element of the periodic table having electronic configuration of $1s^22s^22p^63s^2$

This element will loose 2 electrons to form $Mg^{2+}$ ion

Chlorine is the 17th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^5$

This element will gain 1 electron to form $Cl^{-}$ ion

So, for every 1 atom of magnesium, 2 atoms of chlorine are required. Thus, the chemical formula becomes $MgCl_2$

Hence, the ionic compound formed is magnesium chloride having formula $MgCl_2$

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2 years ago

How to calculate percentage change in mass

blondinia [14]

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This calculation shows what proportion of the initial </span>mass<span> changed. To find the </span>percent change<span>, simply multiply this number by 100</span>

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2 years ago