If the results of an experiment disprove a hypothesis, then the a. results should not be reported. b. hypothesis is just a theor
1 answer:
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First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)
Let's find the molecular mass of each element.
Now, let's find the mass of each compound.
We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.
Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).
Turn that into a percentage and you get 45.431%.
Hope this helps! :)
(Note: the unit of measurement for mass will be amu)
Let's find the molecular mass of each element.
Now, let's find the mass of each compound.
We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.
Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).
Turn that into a percentage and you get 45.431%.
Hope this helps! :)
Answer:
28.9%
Explanation:
Let's consider the following balanced equation.
2 FeS₂ + 11/2 O₂ ⇒ Fe₂O₃ + 4 SO₂
We can establish the following relations:
- The molar mass of Fe₂O₃ is 159.6 g/mol
- 1 mole of Fe₂O₃ is produced per 2 moles of FeS₂
- 1 mole of Fe is in 1 mole of FeS₂
- The molar mass of Fe is 55.84 g/mol
The amount of Fe in the sample that produced 0.516 g of Fe₂O₃ is:
The percent of Fe in 1.25 g of the ore is: