Answer:
The Unknown V was shiny and gray, but it was a lightweight metal. THE UNKNOWN METALS5V was aluminum, which has a density of 2.75 g/ml(Smith, 2019).
Explanation:
pls mark me as brainleast and folow me
NaOH+HCl-> NaCl+H2O
1 mole of NaOH
1 mole of HCl.
To calculate volume of NaOH
CaVa/CbVb= Na/Nb
Where Ca=2M
Cb=1M
Va=200cm³
Vb=xcm³
Substitute into the equation.
2×200/1×Vb=1/1
400/Vb=1/1
Cross multiply
Vb×1=400×1
Vb=400cm³
To calculate the mass of sodium chloride, NaCl from the neutralization rxn.
Mole of NaCl=1
Molar mass of NaCl= 23+35.5=58.5
Mass=xgrammes.
Mass of NaCl=Number of moles × Molar mass.
Substitute
Mass of NaCl= 1×58.5
=58.5g
This is what I could come up with.
2Ca(OH)2(aq) + 2FeCl3(aq) on the dead locs
Answer:

Explanation:
Hello,
In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

Thus, solving for the moles of the acid, we obtain:

Then, by using the mass of the acid, we compute its molar mass:

Regards.