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vampirchik [111]
3 years ago
5

A distinct layer within a soil profile is called a/an

Physics
1 answer:
posledela3 years ago
8 0
A distinct layer within a soil profile is called a soil horizon. 
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When a simple magnifying glass is used properly, the image will be formed
just olya [345]

Magnifying glasses typically use a value of 0.25 meters, or 250 millimeters, distance. This means that that D is the correct answer and the image will be formed approximately D. 250 millimeters in front of the lens

3 0
3 years ago
5. If the momentum of a body is increased by 100% then the percentage increase in kinetic
Mnenie [13.5K]
The answer is the letter ( d )
5 0
3 years ago
Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.
iragen [17]

Answer:

y = 27 cm

Explanation:

given,

After 11 hours of burning height of candle is 27.9 cm

After 30 hours of burning height of candle is 26 cm

height after 20 hour = ?

the candle height decreases linearly

using linear equation

y = m x+ c

27.9 = m (11 ) + C.......(1)

26 = m (30) + C..............(2)

on solving equation (1) and (2)

1.9 = -19 m

m = -0.1

from equation 2

26 = -3 + C

C = 29

y = m x + 29

at 20 hour

y = -0.1× 20 + 29

y = 27

height of candle after 20 hours is 27 cm.

3 0
3 years ago
When hung from an ideal spring with spring constant k = 1.5 N/m, it bounces up and down with some frequency ω, if you stop the b
Umnica [9.8K]

Answer:

L = ¼ k g / m

Explanation:

This is an interesting exercise, in the first case the spring bounces under its own weight and in the second it oscillates under its own weight.

The first case angular velocity, spring mass system is

    w₁² = k / m

The second case the angular velocity is

    w₂² = L / g

They tell us

    w₂ = ½ w₁

Let's replace and calculate

     √ (L / g) = ½ √ (k / m)

      L / g = ¼ k / m

       

      L = ¼ k g / m

7 0
3 years ago
A 0.106-A current is charging a capacitor that has square plates 6.00 cm on each side. The plate separation is 4.00 mm. (a) Find
FrozenT [24]

Answer:

The time rate of change of flux is 1.34 \times 10^{10} \frac{V}{s}

Explanation:

Given :

Current I = 0.106 A

Area of plate A = 36 \times 10^{-4} m^{2}

Plate separation d = 4 \times 10^{-3} m

(A)

First find the capacitance of capacitor,

   C = \frac{\epsilon _{o} A }{d}

Where \epsilon _{o} = 8.85 \times 10^{-12}

   C = \frac{8.85 \times 10^{-12 } \times 36 \times 10^{-4}  }{4 \times 10^{-3} }

   C = 7.9 \times 10^{-12} F

But   C = \frac{Q}{V}

Where Q = It

  C = \frac{It}{V}

  V = \frac{It}{C}

Now differentiate above equation wrt. time,

  \frac{dV}{dt} = \frac{I}{C}

       = \frac{0.106}{7.9 \times 10^{-12} }

       = 1.34 \times 10^{10} \frac{V}{s}

Therefore, the time rate of change of flux is 1.34 \times 10^{10} \frac{V}{s}

8 0
3 years ago
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