A distinct layer within a soil profile is called a/an

A projectile is launched at an angle 60° to the horizontal

Katena32 [7]

Explanation:

We have,

A projectile is launched at an angle 60° to the horizontal with some initial speed 45 m/s.

The cliff is 265 m high.

(A) The final velocity of the projectile is given by :

$v_f^2-v_i^2=2gs\\\\v_f^2=2gs+v_i^2\\\\v_f^2=2\times 9.8\times 265+45^2\\\\v_f=84.96\ m/s$

(B) The maximum height of the projectile is given by :

$H=\dfrac{v_i^2\sin^2\theta}{2g}\\\\H=\dfrac{45^2\times \sin^2(60)}{2\times 9.8}\\\\H=77.48\ m$

(C) The horizontal range of the motion is given by :

$R=\dfrac{v_i^2\sin 2\theta}{g}\\\\R=\dfrac{(45)^2\times \sin 2(60)}{9.8}\\\\R=178.94\ m$

7 0

4 years ago

A truck driving along a highway road has a large quantity of momentum. If it moves at the same speed but has twice as much mass,

oee [108]

If the truck moves at same speed but twice as much mass, its momentum is increased twice.

Answer:

Explanation:

Momentum is defined as the force experienced by any object for a given time. In other words, it is the measure of the mass and velocity required for a certain motion. So it is determined as the product of mass and velocity of any object.

Momentum = Mass × Velocity.

As momentum is directly proportional to both mass and velocity, increase in any one of these two quantities keeping the other constant will lead to increase in the momentum.

So in the present case, it is stated as speed is kept constant and the mass is increased twice, then the momentum will also increase twice.

New momentum = 2 ×mass × velocity = 2 × old momentum

If the truck moves at same speed but twice as much mass, its momentum is increased twice.

3 0

4 years ago

Please Help. I would Really Appreciate it

Readme [11.4K]

Answer:

a) 0.60 kg cart has final velocity 3.0 m/s [E]

0.80 kg cart has final velocity 4.0 m/s [W]

b) 0.12 m

Explanation:

Take east to be positive.

a) Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.60) (-5.0) + (0.80) (2.0) = (0.60) v₁ + (0.80) v₂

-1.4 = 0.6 v₁ + 0.8 v₂

Kinetic energy is conserved in elastic collisions.

½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²

m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²

(0.60) (-5.0)² + (0.80) (2.0)² = (0.60) v₁² + (0.80) v₂²

18.2 = 0.6 v₁² + 0.8 v₂²

Solve the system of equations.

-1.4 = 0.6 v₁ + 0.8 v₂

-1.4 − 0.6 v₁ = 0.8 v₂

-1.75 − 0.75 v₁ = v₂

18.2 = 0.6 v₁² + 0.8 (-1.75 − 0.75 v₁)²

18.2 = 0.6 v₁² + 0.8 (3.0625 +2.625 v₁ + 0.5625 v₁²)

182 = 6 v₁² + 8 (3.0625 + 2.625 v₁ + 0.5625 v₁²)

182 = 6 v₁² + 24.5 + 21 v₁ + 4.5 v₁²

0 = 10.5 v₁² + 21 v₁ − 157.5

0 = v₁² + 2 v₁ − 15

0 = (v₁ − 3) (v₁ + 5)

v₁ = 3 or -5

Since u₁ = -5.0 m/s, v₁ must be 3.0 m/s.

Solving for v₂:

v₂ = -0.75 v₁ − 1.75

v₂ = -4.0 m/s

b) The compression of the spring is a maximum when the carts have the same velocity.

Momentum is conserved.

m₁u₁ + m₂u₂ = (m₁ + m₂) v

(0.60) (-5.0) + (0.80) (2.0) = (0.60 + 0.80) v

-1.4 = 1.4 v

v = -1.0

Energy is conserved.

½ m₁u₁² + ½ m₂u₂² = ½ (m₁ + m₂) v² + ½ kx²

m₁u₁² + m₂u₂² = (m₁ + m₂) v² + kx²

(0.60) (-5.0)² + (0.80) (2.0)² = (0.60 + 0.80) (-1.0)² + (1200) x²

18.2 = 1.4 + 1200 x²

16.8 = 1200 x²

x² = 0.014

x = 0.12

5 0

4 years ago

While you are looking at the image of your feet in a plane mirror, you see a scratch in the glass. What is the approximate heigh

Montano1993 [528]

Answer:

1.75 / 2 = 0.875 m

Explanation:

Provided the mirror is vertical and you are standing upright.

It could be most any altitude if the mirror is allowed any orientation.

3 0

3 years ago

A car headed north at 15.0 m/s experiences an acceleration of 2.50 m/s2 for 3.00 s. What is the final velocity of the car?

nikitadnepr [17]

Answer:

i dond no can you put another question

4 0

2 years ago