Answer:
D. ? Its the only one talking about color
Answer:
Explanation:
Radius of the ball is ![R=11cm=0.11m](https://tex.z-dn.net/?f=R%3D11cm%3D0.11m)
Initial speed of the ball is ![v_{com0}=6.0m/s](https://tex.z-dn.net/?f=v_%7Bcom0%7D%3D6.0m%2Fs)
Initial angular speed of the ball is ![\omega = 0](https://tex.z-dn.net/?f=%5Comega%20%3D%200)
Coefficient of kinetic friction between the ball and the lane
is ![\mu =0.35](https://tex.z-dn.net/?f=%5Cmu%20%3D0.35)
Due to the presence of frictional force, ball moves with
decreasing velocity.
(a)
velocity
in terms of
is
![V_{com0} = -R\omega\\\\=-(0.11m)\omega\\\\= (-0.11\omega)m/s](https://tex.z-dn.net/?f=V_%7Bcom0%7D%20%3D%20-R%5Comega%5C%5C%5C%5C%3D-%280.11m%29%5Comega%5C%5C%5C%5C%3D%20%28-0.11%5Comega%29m%2Fs)
(b)
Ball's linear acceleration is given by
![a=-\mu g\\\\=-(0.35) (9.8 m/s^2)\\\\= -3.43m/s^2](https://tex.z-dn.net/?f=a%3D-%5Cmu%20g%5C%5C%5C%5C%3D-%280.35%29%20%289.8%20m%2Fs%5E2%29%5C%5C%5C%5C%3D%20-3.43m%2Fs%5E2)
(c)
During sliding, ball's angular acceleration is calculated as
![\alpha=-\frac{\tau}{I}\\\\-\frac{\mu mgR}{(\frac{2}{5}mR^2)}\\\\-\frac{2}{5}\frac{\mu g}{R}\\\\-\frac{2}{5}\frac{(0.35)(9.8)}{0.11}\\\\-77.95rad/s^2](https://tex.z-dn.net/?f=%5Calpha%3D-%5Cfrac%7B%5Ctau%7D%7BI%7D%5C%5C%5C%5C-%5Cfrac%7B%5Cmu%20mgR%7D%7B%28%5Cfrac%7B2%7D%7B5%7DmR%5E2%29%7D%5C%5C%5C%5C-%5Cfrac%7B2%7D%7B5%7D%5Cfrac%7B%5Cmu%20g%7D%7BR%7D%5C%5C%5C%5C-%5Cfrac%7B2%7D%7B5%7D%5Cfrac%7B%280.35%29%289.8%29%7D%7B0.11%7D%5C%5C%5C%5C-77.95rad%2Fs%5E2)
(d)
The time for which the ball slides is calculated from the
equation of motion is
![V_{cm}= V_{cm0} + at\\\\V_{cm} = V_{cm0} + (-\mu g )t\\\\-0.11\omega=6.0m/s -(3.43m/s^2 )t\\\\-(0.11) (\alpha t) =6.0 m/s - (3.43 m/s^2)\\\\- (0.11)(-77.95 rad/s^2)t = 6.0m/s - (3.43 m/s^2 )t\\\\8.5745t + 3.43t= 6.0\\\\12.0045t = 6.0\\\\t= 0.4998s](https://tex.z-dn.net/?f=V_%7Bcm%7D%3D%20V_%7Bcm0%7D%20%2B%20at%5C%5C%5C%5CV_%7Bcm%7D%20%3D%20V_%7Bcm0%7D%20%2B%20%28-%5Cmu%20g%20%29t%5C%5C%5C%5C-0.11%5Comega%3D6.0m%2Fs%20-%283.43m%2Fs%5E2%20%29t%5C%5C%5C%5C-%280.11%29%20%28%5Calpha%20t%29%20%3D6.0%20m%2Fs%20-%20%283.43%20m%2Fs%5E2%29%5C%5C%5C%5C-%20%280.11%29%28-77.95%20rad%2Fs%5E2%29t%20%3D%206.0m%2Fs%20-%20%283.43%20m%2Fs%5E2%20%29t%5C%5C%5C%5C8.5745t%20%2B%203.43t%3D%206.0%5C%5C%5C%5C12.0045t%20%3D%206.0%5C%5C%5C%5Ct%3D%200.4998s)
(e)
Distance traveled by the ball is
![X= V_{com,0}+ \frac{1}{2}at^2\\\\= (6.0m/s)(0.4998 s)+ 0.5(-3.43m/s^2) (0.4998 s)^2\\\\=2.57m](https://tex.z-dn.net/?f=X%3D%20V_%7Bcom%2C0%7D%2B%20%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5C%5C%3D%20%286.0m%2Fs%29%280.4998%20s%29%2B%200.5%28-3.43m%2Fs%5E2%29%20%280.4998%20s%29%5E2%5C%5C%5C%5C%3D2.57m)
(for)
The speed of the ball when smooth rolling begins is
![V_{cm} = V_{com, 0}+ at\\\\=6.0 m/s +(-3.43m/s^2 )(0.4998 s)\\\\= 4.29m/s](https://tex.z-dn.net/?f=V_%7Bcm%7D%20%3D%20V_%7Bcom%2C%200%7D%2B%20at%5C%5C%5C%5C%3D6.0%20m%2Fs%20%2B%28-3.43m%2Fs%5E2%20%29%280.4998%20s%29%5C%5C%5C%5C%3D%204.29m%2Fs)
Answer:
its b
Explanation:
ohm is the unit of resistance
Higher frequency,higher energy,shorter wavelength