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Grace [21]
3 years ago
8

Gelatin has a density of 1.27 g/cm³. if you have a blob of gelatin dessert that fills a 2.0 liter bottle, what is its mass?

Physics
2 answers:
lyudmila [28]3 years ago
7 0
There are 1,000 cm³ in 1 liter, 2,000 cm³ in 2 liters.

Each cm³ of gelatin has  1.27 grams of mass in it.

There are 2,000 cm³ in the whole blob, so the total mass is

            (2,000 cm³) · (1.27 g/cm³)  =  2,540 grams

                                                         or    2.540 kilograms  .
Verdich [7]3 years ago
6 0
Density = mass / volume so mass = density x volume

2 litres = 2000cm^3


mass = 1.27 x 2000 = 2540g = 2.54 kg
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The minimum speed of the water must be 3.4 m/s

Explanation:

There are two forces acting on the water in the pail when it is at the top of its circular motion:

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  • The normal reaction, N also acting downward

Since the water is in circular motion, the net force must be equal to the centripetal force, so:

N+mg=m\frac{v^2}{r}

Where:

g=9.8 m/s^2

v is the speed of the pail

r = 1.2 m is the radius of the circle

The water starts to spill out when the normal reaction of the pail becomes zero:

N = 0

When this occurs, the equation becomes:

mg=m\frac{v^2}{r}\\v=\sqrt{gr}

And substitutin the values of g and r, we find the minimum speed that the water must have in order not to spill out:

v=\sqrt{(9.8)(1.2)}=3.4 m/s

Learn more about circular motion:

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brainly.com/question/6372960

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6 0
3 years ago
Assume you are given an int variable named nElements and a two-dimensional array that has been created and assigned to a2d. Writ
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Answer:

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Explanation:

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3 0
3 years ago
As an object moves, the distance it travels increases with time.<br><br> Agree<br> Disagree
Mnenie [13.5K]
Agree

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4 0
3 years ago
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4 0
2 years ago
You are given a vector in the xy plane that has a magnitude of 90.0 units and a y component of -61.0 units. A) Assuming the x co
kvasek [131]

Answer:

A) magnitude = sqrrt(147.1^2 + 61^2) = 159.2 units

B)22.5° (clockwise form -ve X axis)

Explanation:

given vector = V1 = x i - 60 j

magnitude of V1 = 90

x - component can be found out by resultant formula

90^2 = x^2 + (-60)^2

x = 67.08 = 67.1 units (3sf)

FOR THE VECTOR 80 UNITS IN -VE X DIRECTION

The X component is -80-------(1)

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<u>For the x- component of new added vector:</u>

(1)----------- x + 67.1 = -80

x = -147.1 = -147.1

<u>For the y- component of new added vector:</u>

<u>(</u>2)---------- y - 61  = 0

y = 61.0 (3sf)

the new added vector is  = -147.1 i + 61 j

magnitude = sqrrt(147.1^2 + 61^2) = 159.2 units

direction = arctan (61 / 147.1)

               = 22.5° (clockwise form -ve X axis)

<u />

4 0
3 years ago
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