Question

Consider a traveling wave described by the formula

Answer 1

Answer:

The wave is traveling in the +x direction.

Explanation:

The equation of a wave is given by the formula as :

$y(x,t)=A\ sin(kx-\omega t)$

Here,

A is the amplitude of wave

$(kx-\omega t)$ is the phase of wave

$\omega$ is the angular frequency of the wave

We need to find the correct statement out of given options. The given equation can be rewritten as :

$y(x,t)=A\ sin(\omega t-kx)$

Here, the propagation constant is negative. So, the wave is moving in +x direction. Hence, the correct option is (a).