All categories

2 years ago

A car with a mass of 1,500 kg is accelerating at a rate of

Physics

1 answer:

AURORKA [14]2 years ago

4 0

Answer:

The net force acting on the car is

Newtons.

Hope this helps you

Explanation:

Force is defined as the product of the mass of the body and its aaceleration,

⇒

Substituting the above given values we get,

(

1500

)

(

2.0

)

3000

You might be interested in

What is the universe made of? Astronomers face an embarrassing conundrum: they don't know what 95% of the universe is made of

rewona [7]

Answer:

This what they all been waiting for

I guess so

They been waiting for this sh,it for a long time didn't they

I'ma give it everything I got

Ayo Dougie park that X6 around the corner

Aye I'm just feeling my vibe right now

I'm feeling myself

Explanation:

3 0

3 years ago

How would playing a game of soccer, baseball, or basketball be different if inertia didn't exist?

BigorU [14]

Inertia is what keeps everything moving, so if it didn't exist, the balls wouldn't keep going when they are kicked, or thrown.

4 0

3 years ago

What happens when you decrease the thrust on your scooter? A. You stop B. Nothing happens C. You fall over D. You speed up Reset

mars1129 [50]

Answer:

D. You speed up

Explanation:

hope it helps

4 0

2 years ago

What type of configuration is used in the HEVs available in the US today?

Citrus2011 [14]

Answer:

Currently in the united states using parallel system

Explanation:

because you can walk with the twomodes with internal combustion engine or running on electric power.

6 0

1 year ago

by how many times occur in the force of attraction between two bodies change when the distance between then is reduced to one th

xenn [34]

Answer:

<em>The force is now 9 times the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Coulomb's formula is:

$\displaystyle F=k\frac{q_1q_2}{d^2}$

Where:

$k=9\cdot 10^9\ N.m^2/c^2$

q1, q2 = the particles' charge

d= The distance between the particles

Suppose the distance is reduced to d'=d/3, the new force F' is:

$\displaystyle F'=k\frac{q_1q_2}{\left(\frac{d}{3}\right)^2}$

$\displaystyle F'=k\frac{q_1q_2}{\frac{d^2}{9}}$

$\displaystyle F'=9k\frac{q_1q_2}{d^2}$

$\displaystyle F'=9F$

The force is now 9 times the original force

8 0

2 years ago