<u>Answer:</u>
a. Oxidising agent: Cl₂
b. Reducing agent: NaBr
c. Oxidised: NaBr
d. Reduced: Cl₂
e. Oxidation numbers before reaction: Cl= 0, Na= +1, Br= -1
f. Oxidation numbers after reaction: Cl= -1, Na= +1, Br= 0
<u>Explanation:</u>
Oxidising agents reduces themselves, oxidising other elements/compounds.
Reducing agents oxidise themselves, reducing other elements/compounds.
Oxidation is the <u>loss</u> of electrons or an <u>increase</u> in oxidation number.
Reduction is the <u>gain</u> of electrons or <u>decrease</u> in oxidation number.
The answer is d: <span>light waves you can see and waves of both higher and lower energy radiation.
The electromagnetic spectrum is the spectrum of all frequencies of electromagnetic (or light) radiation. The visible spectrum is a small range of these frequencies.</span>
Complete question:
The student performs a second titration using the 0.10MNaOH(aq) solution again as the titrant, but this time with a 20.mL sample of 0.20MHCl(aq) instead of 0.10MHCl(aq).
1. The box below to the left represents ions in a certain volume of 0.10MHCl(aq). In the box below to the right, draw a representation of ions in the same volume of 0.20MHCl(aq). (Do not include any water molecules in your drawing.)
Answer:
The concentration of H+ and Cl- will be doubled.
Explanation:
See the attached photo for the representation of ions in the same volume.
Explanation:
Mass of solution , m= 0.94 g + 215 g = 215.94 g
Volume of the solution = V
Density of solution = d =
Moles of hydrogen =
Molarity of hydrogen gas:
Molality of hydrogen gas :
Mass of solvent or here it is palladium = 215 g =0.215 kg (1 g = 0.001 kg)
Mass percentage of hydrogen is solution :
The question is incomplete, the complete question is;
Calculate the volume of concentrated HCL (12 M) needed to convert 1.5 g of sodium benzoate back to benzoic acid.
Answer:
8.33 * 10^-4 L
Explanation:
Equation of the reaction;
C6H5COONa + HCl -------->>>> C6H5COOH + NaCl
Number of moles of sodium benzoate = mass/molar mass
molar mass of sodium benzoate =144.11 g/mol
mass of sodium benzoate = 1.5 g
Number of moles of sodium benzoate = 1.5g/144.11 g/mol
Number of moles of sodium benzoate = 0.01 moles
Since the reaction is 1:1, 0.01 moles of HCl reacted.
but;
n = CV
n = number of moles
C = concentration
V = volume
V = n/C
V = 0.01 moles/12 M
V = 8.33 * 10^-4 L