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tatiyna
3 years ago
9

A molecule of aluminum fluoride has one aluminum atom. How many fluorine atoms are present?

Chemistry
2 answers:
svlad2 [7]3 years ago
8 0

Answer:

3 fluorine atoms will be present

Jlenok [28]3 years ago
6 0

Answer:

3

Explanation:

The chemical formula of aluminum fluoride is AlF3. As you can see, there is a 1:3 ratio of aluminum atoms to fluorine atoms. Therefore, if a molecule of AlF3 has one aluminum atom, you know there must be 3 fluorine atoms present.

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Compare land cover and land use, explaining how they are related and describing one way that humans can affect that relationship
Natali5045456 [20]

Answer:

Land covers refer to all the manufactured structures and vegetation that covers the land it includes all vegetation including plants, shrubs, trees, and other man-made structures too.

On other hand, Land use is the term that explains the use of the land by the different human activities that are occurred on land that are directly related to the land.

Land cover influences land use by utilizing particular land such as parks, ponds, or other uses according to the land. and humans can cause changes in both when they urbanize the area or land.

5 0
3 years ago
What is the molecular formula for the compound with a formula mass of 58.12 and an empirical formula of c2h5?
LenKa [72]
The molecular formula is C4H10.
3 0
3 years ago
Read 2 more answers
Bromine- is radioactive and has a half life of seconds. What percentage of a sample would be left after seconds? Round your answ
Vladimir [108]

Corrected question:

Bromine-88 is radioactive and has a half life of 16.3seconds. What percentage of a sample would be left after 35seconds? Round your answer to 2 significant digits.

Answer:

23% (3 significant digits)

Explanation:

M_{R} =\frac{M_{O} }{2^{n} }

where M_{R} is mass remaining

          M_{O} is original mass

          n=\frac{t}{t1/2}

       t1/2= 16.3s  ,  t=35s

n =35/16.3 =2.147

M_{R} =\frac{M_{O} }{2^{2.147} }

M_{R} = 0.2258M_{O}

0.2258*100% =22.5%

≈23%

5 0
4 years ago
What mass of Ca(NO3)2 is equal to 0.75 moles of this substance?
sattari [20]

Answer:

Ca - 63.546 g

2N - 28.014 g

2O3 - 96 g

Ca(NO3)2 = 187.56 g

187.56 g x 0.75 mol = 140.67 g

Explanation:

Hope this helps

5 0
3 years ago
Are these equations balanced? If not how do I balance them?
wlad13 [49]

Answer:

The answer to your question is given below.

Explanation:

1. CH3COOH(aq) + NaHCO3(s) —> CO2(g) + H2O(l) + Na+(aq) + CH3COO-(aq)

The above equation is balanced since the number of atoms of the different elements present on both sides of the equation are equal.

2. CaCl2 + NaHCO3 —> CO2 + CaCO3 + NaCl + H2O

The above equation can be balance as follow:

There are 2 atoms of Cl on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NaCl as shown below:

CaCl2 + NaHCO3 —> CO2 + CaCO3 + 2NaCl + H2O

Now, there are 2 atoms of Na on the right side and 1 atom on the left side. It can be balance by putting 2 in front of NaHCO3 as shown below:

CaCl2 + 2NaHCO3 —> CO2 + CaCO3 + 2NaCl + H2O

Now the equation is balanced.

3 0
3 years ago
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