Reorder 4Fe and 3O2.
3O2 + 4Fe
Answer:
The resultant molarity is 0,7 M.
Explanation:
A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).
We use the formula for dilutions:
C1 x V1 = C2 x V2
3,5 M x 20 ml= C2 x 100ml
C2= (3,5 M x 20 ml)/100ml
<em>C2= 0,7M</em>
Answer:
Like the inert gases(noble gases).
Explanation:
Data:
M (molarity) = ? (M or Mol/L)
m (mass) = 13.50 g
V (volume) = 250 mL → 0.25 L
MM (Molar Mass) of Lead(IV) Nitrate

Pb = 1*207 = 207 amu
N = (1*14)*4 = 14*4 = 56 amu
O = (3*16)*4 = 48*4 = 192 amu
------------------------------------
MM of

= 207+56+192 = 455 g/mol
Formula:

Solving:




Answer:
<span>
B. 0.119 M</span>
Answer:
Weak acid and base solutions contain multiple charged and uncharged species in dynamic equilibrium. Strong acids and strong bases refer to species that completely dissociate to form ions in solution.
Explanation: