Ask question

Ask question

All categories

harkovskaia [24]

3 years ago

13

An ionic compound has the general formula, XCl2. Element X comes from which group? Justify your answer with an explanation and p

rovide an example.

1 answer:

Rashid [163]3 years ago

6 0

Answer:

metal group

Explanation:

ionic bond = nonmetal + metal

Cl = nonmetal (you need a metal0

ex. LiCl2 or CaCl2

- Hope that helped! Let me know if you need a further explanation.

You might be interested in

Select all of the ways collection areas use to gain water. precipitation falls direction into the collection area runoff from pr

MrRissso [65]

The answer will be A & B not only because it makes sense but evaporation is taking water away not adding to (gaining)

4 0

3 years ago

The threat of another hurricane is a problem for New York City. What have people

Maksim231197 [3]

Answer:

idk

Explanation:

4 0

3 years ago

Read 2 more answers

What is reproduction

Zolol [24]

The action or process of making a copy of something.

3 0

3 years ago

Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr

VikaD [51]

Answer : The value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

Explanation :

The balanced cell reaction will be,

$Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)$

The half-cell reactions are:

Oxidation reaction (anode) : $Pb(s)\rightarrow Pb^{2+}(aq)+2e^-$

Reduction reaction (cathode) : $2Ag^+(aq)+2e^-\rightarrow 2Ag(g)$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

$\Delta G^o$ = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

$\Delta G^o=-2\times 96500\times 0.93$

$\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol$

Now we have to calculate the value of 'K'.

$\Delta G^o=-RT\ln K$

where,

$\Delta G_^o$ = standard Gibbs free energy = -180 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

$-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K$

$K=3.6\times 10^{31}$

Therefore, the value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

5 0

3 years ago

A plane mirror is useful for seeing:

AURORKA [14]

C. A nearly identical image.

6 0

3 years ago