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Hatshy [7]
4 years ago
12

It is often more convenient to express distance in ????m rather than m and frequency in ????Hz rather than Hz. Rewrite the equat

ion for free space loss, ???????????? = 20 log ???? + 20 log ???? − 147.56 ????????, using the new dimension units.
Physics
1 answer:
Bumek [7]4 years ago
8 0

Answer:

L (in dB) = 20 log f + 20 log d + 32.44

with f in MHz and d in Km

Explanation:

L(in dB) = 20 log f + 20 log d - 147.56 dB

with f in Hz and D in m

MHz = 10⁶ Hz

And

Km = 10³ m

L(in dB) = 20 log f + 20 log d - 147.56 dB

L = 20 log [10⁶f] + 20 log [10³d] - 147.56

L = 20 log 10⁶ + 20 log f + 20 log 10³ + log d - 147.56

From the law of logarithms,

Log 10⁶ = 6

Log 10³ = 3

L = (20×6) + (20×3) + 20 log f + 20 log d - 147.56

L = 20 log f + 20 log d - 147.56 + 120 + 60

L (in dB) = 20 log f + 20 log d + 32.44

Hope this Helps!!!

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const2013 [10]

Answer:

True

Explanation:

Cigarettes release over 5000 different chemicals when they burn and at least 70 of these can cause cancer.

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7 0
3 years ago
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When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00  10 5J of work are done. Find this final speed.
Akimi4 [234]
  • Mass=1167kg
  • Initial velocity=u=10m/s
  • Acceleration=a=4m/s^2
  • Work done=105J=W
  • Final velocity=v=?
  • Force=F
  • Distance=d

Apply Newton's second law

\\ \tt\hookrightarrow F=ma

\\ \tt\hookrightarrow F=1167(4)=4668N

Now

\\ \tt\hookrightarrow W=Fd

\\ \tt\hookrightarrow d=\dfrac{W}{F}

\\ \tt\hookrightarrow d=\dfrac{105}{4668}

\\ \tt\hookrightarrow d=0.022m

Now

  • d be s

According to third equation of kinematics

\\ \tt\hookrightarrow v^2=u^2+2as

\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)

\\ \tt\hookrightarrow v^2=100+8(0.022)

\\ \tt\hookrightarrow v^2=100+0.176

\\ \tt\hookrightarrow v^2=100.176

\\ \tt\hookrightarrow v=10.001m/s

8 0
2 years ago
A 21500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the
GalinKa [24]

Answer:\theta =79.47 North\ of\ west

Explanation:

Given

Mass of airplane =21500 kg

Force due to jet engines=35100 N

Force from wind is 14900 N at angle of 75 south of west

Resolving forces

F_x=14900cos75=-3856.403 N

F_y=35100-14900sin75

F_y=35100-14392.29=20707.70 N

Therefore acceleration in x direction

a_x=\frac{F_x}{m}=\frac{-3856.403}{21500}=-0.179 m/s^2

a_y=\frac{F_y}{m}=\frac{20707.70}{21500}=0.963 m/s^2

Direction of acceleration

tan\theta =\frac{a_y}{a_x}=\frac{0.963}{0.179}=-5.38

\theta =79.47\ North\ of\ west

5 0
4 years ago
20. There are two electrical devices, one is electrical kettle of 2KW-200V and
RUDIKE [14]

Electrical kettle:  

P = 2 KW = 2000 W

U = 200 V

⇒  I = P/U = 2000 / 200 = 10 A

We apply the Law of Ohm:

R = U / I = 200V / 10A = <u>20 Ω</u>

=======

Electrical heater:

P = 1 KW = 1000 W

U = 240 V

⇒  I = P/U = 1000 / 240 = 4,16 A

We apply the Law of Ohm:

R = U / I = 240V / 4,16A = <u>57,69 Ω</u>

<u>Answer:</u>

The device with the highest resistance is <u>the electric heater.</u>

<u></u>

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<u></u>

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