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Aleks04 [339]
4 years ago
9

A student throws a heavy red ball horizontally from a balcony of a tall building with an initial speed v0. At the same time, a s

econd student drops a lighter blue ball from the same balcony. Which ball hits the ground first?
Physics
2 answers:
max2010maxim [7]4 years ago
7 0

Answer:

Both balls reach the ground at the same time.

Explanation:

You may ask why? Well, the first ball is thrown with a horizontal velocity, but the acceleration it has is the gravity, so it will have an accelerated motion on the Y axis, so if we drop a second ball at the same time it will have the same acceleration going down, so both balls reach the ground at the same instant, the first ball will have a horizontal displacement but it'll reach at the same time.

Vlada [557]4 years ago
4 0
I'm not sure but I think both of the balls hit the ground at the same instant.
Because according to the laws of gravitation, all objects accelerate in the same rate under gravity. Whether a heavy object or a lightweight one, if there is no air resistance, both fall with the same speeds if their initial speeds were zero. So, the have the same final speeds before reaching the ground. Remember that acceleration due to gravity is independent of mass.
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HACTEHA [7]

Answer:

A scientific model is a way of representing a system to better understand it's behavior

Explanation:

5 0
3 years ago
Why is it warmer near the equator and cooler near the poles?
Phantasy [73]
It is because the equator is closer to the sun and because the sun's rays hit the surface of the Earth at a higher angle at the equator. The poles are colder because they don't get direct sunlight. The sun is always low on the horizon.
8 0
4 years ago
Read 2 more answers
A uniform electric field of 2 kNC-1 is in the x-direction. A point charge of 3 μC initially at rest at the origin is released. W
ANEK [815]
The electric force acting on the charge is given by the charge multiplied by the electric field intensity:
F=qE
where in our problem q=3 \mu C= 3 \cdot 10^{-6} C and E=2 kN/C=2000 N/C, so the force is
F=(3 \cdot 10^{-6} C)(2000 N/C)=0.006 N

The initial kinetic energy of the particle is zero (because it is at rest), so its final kinetic energy corresponds to the work done by the electric force for a distance of x=4 m:
K(4 m)=W=Fd=(0.006 N)(4 m)=0.024 J
8 0
3 years ago
A puck of mass 0.5100.510kg is attached to the end of a cord 0.8270.827m long. The puck moves in a horizontal circle without fri
yanalaym [24]

Answer: 2.75 1/sec

Explanation:

The only external force (neglecting gravity) acting on the puck, is the centripetal force, which. in this case, is represented by the tension in the string, so we can say:

T = mv² / r (1)

Our unknown, is the frequency at which the puck can go around the circle, which is the inverse of the period Tp.

By definition, a period is the time needed by the puck to complete one entire circle.

By definition also , angular velocity is the rate of change of the angle advanced, so we can express this way:

ω = ∆θ / ∆t  

The angle advanced during one period, is exactly (by angle definition) 2 π radians.

So, we can always write the angular velocity, ω, as follows:

ω = 2π / Tp = 2πf

Now, there is a relationship between linear and angular velocity, that can be found applying simply the definition of velocity and of an angle too, as follows:

v = ∆s / ∆t = r ∆θ/∆t = ω r

Replacing in (1), we have:

T = mω2 r2 / r = m ω2r (2)

We have just found that ω= 2πf, so, replacing in (2) :

T = m (2π)2 f2 r  

Solving for f:

f = 1/2π√(T/mr) = 1/2π 17.28 1/sec = 2.75 1/sec

6 0
3 years ago
How much energy goes toward kinetic energy
kirill [66]

kinetic is moving

so kinetic energy is something that moves

8 0
3 years ago
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