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3 years ago

2. How does the medium vibrate in a transverse wave?

Physics

1 answer:

stiv31 [10]3 years ago

3 0

ANSWER :

(A) AT RIGHT ANGLES TO THE DIRECTION THE WAVE TRAVELS.

EXPLANATION :

TRANSVERSE WAVES IS THAT IN WHICH THE PARTICLES VIBRATE WITH AN UP-AND-DOWN MOTION. THE PARTICLES IN A TRANSVERSE WAVE MOVE ACROSS OR PERPENDICULAR TO THE DIRECTION THAT THE WAVE IS TRAVELING OR AT RIGHT ANGLES TO THE DIRECTION THE WAVE TRAVELS.

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A bicyclist with a mass of 50 kg is traveling at a rate of 30 m/s. It accelerates to a rate of 50 m/s in 5 seconds. What is the

balandron [24]

Answer:

F=m*(v^2/r)

F=82*(8^2/30)

F=174.9N

Explanation:

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3 years ago

You are heading toward an island in your speed boat when you see a friend standing on the shore of the island. You sound the boa

monitta

Answer:

Greater than

Explanation:

The Wavelength will be higher than what will be heard without any motion on the boat due to the Doppler Effect, which is the change in the frequency of a sound wave whenever there's a relative motion between the source of the wave and observer. The amount of shift in frequency depends on the speed of the source towards the observer; the higher the velocity of the source, the higher the shift.

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3 years ago

A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How man

Ne4ueva [31]

Answer:

A. α = - 1.047 rad/s²

B. θ = 14.1 rad

C. θ = 2.24 rev

Explanation:

We can use the first equation of motion to find the acceleration:

$\omega_f = \omega_i + \alpha t$

where,

ωf = final angular speed = 0 rad/s

ωi = initial angular speed = (30 rpm)(2π rad/1 rev)(1 min/60 s) = 3.14 rad/s

t = time = 3 s

α = angular acceleration = ?

Therefore,

$0\ rad/s = 3.14\ rad/s + \alpha(3\ s)$

α = - 1.047 rad/s²

We can use the second equation of motion to find the angular distance:

$\theta = \omega_it +\frac{1}{2}\alpha t^2\\\theta = (3.14\ rad/s)(3\ s) + \frac{1}{2}(1.04\ rad/s^2)(3)^2$

θ = 14.1 rad

θ = (14.1 rad)(1 rev/2π rad)

θ = 2.24 rev

6 0

3 years ago

Please help me↓

olga2289 [7]

Answer:

unmmm u can say that it is going mt 15s

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3 years ago

What mass of electrons would be required to just neutralize the charge of 4.8 g of protons?

suter [353]

Let's calculate the total charge of M=4.8 g=0.0048 kg of protons.
Each proton has a charge of $q=1.6 \cdot 10^{-19} C$ , and a mass of $m_p = 1.67 \cdot 10^{-27}kg$ . So, the number of protons is
$N_p = \frac{M}{m_p}= \frac{0.0048 kg}{1.67 \cdot 10^{-27}kg}=2.87 \cdot 10^{24}$ And so the total charge of these protons is $Q_p = qN_p = (1.6 \cdot 10^{-19}C)(2.87 \cdot 10^{24})=4.6\cdot 10^5 C$

So, the neutralize this charge, we must have $N_e$ electrons such that their total charge is
$Q_e = -4.6 \cdot 10^5 C$
Since the charge of each electron is $q_e = -1.6 \cdot 10^{-19}C$ , the number of electrons needed is
$N_e = \frac{Q_e}{q}= \frac{-4.6 \cdot 10^5 C}{-1.6 \cdot 10^{-19}C}=2.87 \cdot 10^{24}$
which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is $m_e=9.1 \cdot 10^{-31}kg$ , the total mass of electrons should be
$M_e = N_e m_e = (2.87 \cdot 10^{24})(9.1 \cdot 10^{-31}kg)=2.6 \cdot 10^{-6}kg$

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2 years ago