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LekaFEV [45]
3 years ago
14

How is thermal energy being transferred when steam rises beaker of boiling water?

Physics
1 answer:
liraira [26]3 years ago
5 0

Answer: As long as there is a temperature difference in the system, heat will always move from higher to lower temperatures.

Explanation:

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What are the Vedas?
Citrus2011 [14]

Answer:

B religious writing

Explanation:

The Vedas are a large body of religious texts originating in ancient India. Composed in Vedic Sanskrit, the texts constitute the oldest layer of Sanskrit literature and the oldest scriptures of Hinduism. Hindus consider the Vedas to be apauruṣeya, which means "not of a man, superhuman" and "impersonal, authorless

7 0
2 years ago
An arrow leaves a bow at 60 m/s at an angle of 30 degrees to the horizon.
Orlov [11]

Answer: 11

Explanation:

4 0
2 years ago
water in a cup and a kettle can have the same temperature even though the quantities are different . give reasons​
jekas [21]

Answer:

The reason is because both are exposed to a virtually infinite heat sink, due to the virtually infinite mass  and of the surrounding environment, compared to the sizes of either the cup or the kettle such that the equilibrium temperature, T_{(equilibrium)} reached is the same for both the cup and the kettle as given by the relation;

\infty M_{(environ)} \times  c_{(environ)} \times (T_2 - T_1) = m_{1} \times  c_{(water)} \times (T_3 - T_2) + m_{2} \times  c_{(water)} \times (T_4 - T_2)

Due to the large heat sink, T₂ - T₁ ≈ 0 such that the temperature of the kettle and that of the cup will both cool to the temperature of the environment

Explanation:

4 0
3 years ago
A golf ball is dropped from rest from a height of 9.5m.  It hits the pavement then bounces back up rising  just 5.7 m before fal
Oksanka [162]

Answer: 3.4s

Explanation:

There are three stages in the motion of the ball, so you have to calculate the times for every stage.

1) Ball dropping from 9.5m: free fall

d = Vo + gt² / 2

Vo = 0 ⇒ d = gt² / 2 ⇒ t² = 2d / g = 2 × 9.5 m / 9.81 m/s² = 1.94 s²

⇒ t = √ (1.94 s²) = 1.39s

2) Ball rising 5.7m (vertical rise)

i) Determine the initial speed:

Vf² = Vo² - 2gd

Vf² = 0 ⇒ Vo² = 2gd = 2 × 9.81 m/s² × 5.7m = 111.8 m²/s²

⇒ Vo = 10.6 m/s

ii) time rising

Vf = Vo - gt

Vf = 0 ⇒ Vo = gt ⇒

t = Vo / g = 10.6 m/s / 9.81 m/s² = 1.08 s

3) Ball dropping from 5.7 m to 1.20m above the pavement (free fall)

i) d = 5.7m - 1.20m = 4.5m

ii) d = gt² / 2 ⇒ t² = 2d / g = 2 × 4.5 m / 9.81 m/s² = 0.92 s²

⇒ t = √ (0.92 s²) = 0.96s

4) Total time

t = 1.39s + 1.08s + 0.96s = 3.43s ≈ 3.4s

4 0
3 years ago
Read 2 more answers
What are the foci of the ellipse given by the equation 100x^2 + 64y^2 = 6 400?
NikAS [45]

The equation of our ellipse is:

100 x^2 + 64 y^2 = 6400 (1)

First, let's reduce the equation of the ellipse to the standard form:

\frac{x^2}{a^2}+ \frac{y^2}{b^2}=1

To do that, we should divide both terms of equation (1) by 6400, and we get:

\frac{x^2}{64}+ \frac{y^2}{100}=1

This is a vertical ellipse (because b^2 \ \textgreater \  a^2) centered in the origin, and so the distance of its foci from the origin (on the y axis) is given by

c= \sqrt{b^2-a^2}= \sqrt{(100)-(64)}=6

Therefore, the position of the two foci is (0,6) and (0,-6)

8 0
3 years ago
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