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3 years ago

Find the number of moles in 3.10 x 10^-1g of boron

Chemistry

1 answer:

Sever21 [200]3 years ago

6 0

Answer:

0.0286 moles

Explanation:

Given mass, $m=3.1\times 10^{-1}g=0.31\ g$

Molar mass of boron, M = 10.811 g/mol

$\text{No of moles}=\dfrac{\text{given mass}}{\text{molar mass}}\\\\n=\dfrac{0.31}{10.811 }\\\\n=0.0286$

Hence, there are 0.0286 moles in given mass of boron.

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3 years ago

1.72 mol of LiCl in 37.5 L of solution

givi [52]

<h3>Answer:</h3>

Molarity is 0.046 M

<h3>Explanation:</h3>

We are given;

1.72 mol of LiCl in 37.5 L of solution

We will take the question to be; calculate the molarity of LiCl

Therefore,

we can start by defining molarity as the concentration of a solution in moles per liter.

Molarity of a solution is calculated by dividing the number of moles of solute by the volume of solution.

Molarity = Moles of solute ÷ Volume of the solution

Thus, in this case;

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Therefore, the molarity of LiCl solution is 0.046 M

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3 years ago

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3 years ago

Read 2 more answers

Enter your answer in the provided box. Oxidation of gaseous ClF by F2 yields liquid ClF3, an important fluorinating agent. Use t

MakcuM [25]

Answer : The value of $\Delta H_{rxn}$ for the reaction is, -135.2 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of $ClF_3$ will be,