Answer:
the magnitude of gravitational force is 6 x 10⁻⁸ N.
Explanation:
Given;
mass of the two people, m₁ and m₂ = 90 kg
distance between them, r = 3.0 m
The magnitude of gravitational force exerted by one person on another is calculated as;
where;
G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²
Therefore, the magnitude of gravitational force is 6 x 10⁻⁸ N.
Answer:
<u>real and upside down </u>
Explanation:
Lens of a camera gathers light and focuses it on the light detector or film strip. <u>A real and inverted (upside -down) image is formed. </u>This image is then stored and processed and inverted. Thereafter we see an upright image. A chemical reaction on the film strip stores the image. In a digital lens, a light detector such as CCD stores the image.
Answer:
98N and 147N
Explanation:
We have the following information:
We can find the static fricton force as follow,
Where N is the normal force (mg)
Static friction force at 147N is greater than the force applied hence body does not move.
Answer:
350 ft/s²
Explanation:
First, convert mph to ft/s.
58 mi/hr × (5280 ft/mi) × (1 hr / 3600 s) = 85.1 ft/s
Given:
v₀ = 85.1 ft/s
v = 0 ft/s
t = 0.24 s
Find: a
v = at + v₀
a = (v − v₀) / t
a = (0 ft/s − 85.1 ft/s) / 0.24 s
a = -354 ft/s²
Rounded to two significant figures, the magnitude of the acceleration is 350 ft/s².
