Answer:
the moment of inertia of the merry go round is 38.04 kg.m²
Explanation:
We are given;
Initial angular velocity; ω_1 = 37 rpm
Final angular velocity; ω_2 = 19 rpm
mass of child; m = 15.5 kg
distance from the centre; r = 1.55 m
Now, let the moment of inertia of the merry go round be I.
Using the principle of conservation of angular momentum, we have;
I_1 = I_2
Thus,
Iω_1 = I'ω_2
where I' is the moment of inertia of the merry go round and child which is given as I' = mr²
Thus,
I x 37 = ( I + mr²)19
37I = ( I + (15.5 x 1.55²))19
37I = 19I + 684.7125
37I - 19 I = 684.7125
18I = 684.7125
I = 684.7125/18
I = 38.04 kg.m²
Thus, the moment of inertia of the merry go round is 38.04 kg.m²
Answer:
Velocity, V = 33.33 m/s
Explanation:
Given the following data;
Mass = 180grams to kilograms = 180/1000 = 0.18 kg
Kinetic energy = 100J
To find the speed;
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;

Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Substituting into the equation, we have;
100 = ½*0.18*V²
Cross-multiplying, we have;
200 = 0.18*V²
V² = 200/0.18
V² = 1111.11
Taking the square root of both sides, we have;
Velocity, V = 33.33 m/s
Answer:
r1 -r2 = 3.75cm
Explanation:
Check the attached file for the solution
Frequency = 1/period. ... 1 / 18 sec = (1/18) per sec. That's 0.056 per sec or 0.056 Hz. (rounded)
(5.6 x 10^-2 Hz)
Net force is an unbalanced force, so the object will change speed or direction.
Either the object may speed up or slow down.