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Novay_Z [31]
1 year ago
11

an earthquake 45 km from a city produces p and s waves that ravel outward at 5000 and 3000 m/s, respectively. once city resident

s feel the shaking of the p wave, how much time do they have before the s wave arrives?
Physics
1 answer:
OleMash [197]1 year ago
3 0

By the velocity, the interval time after the p wave arrived is 6 seconds.

We need to know about velocity to solve this problem. Velocity can be determined as the distance traveled divided by time interval. It can be written as

v = s / t

where v is velocity, s is distance and t is the time interval.

From the question above, we know that.

vp = 5000 m/s

vs = 3000 m/s

s = 45 km = 45000 m

Determine the time taken by p wave

tp = s / vp

tp = 45000 / 5000

tp = 9 seconds

Determine the time taken by s wave

ts = s / vs

ts = 45000 / 3000

ts = 15 seconds

The time interval after p waves is

interval time = ts - tp

interval time = 15 - 9

interval time = 6 second

Find more on velocity at: brainly.com/question/25749514

#SPJ4

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Answer:

Reference Point

Explanation:

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When you ride a bike and make a turn, you can feel your body trying to move in the same direction the bike was going. Which of N
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Answer:

C

Explanation:

Newtons second law explains this the most because for every action their is an equal and opposite reaction. The reaction of you turning, causes the reaction of your whole body to turn with the bike.

3 0
3 years ago
Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example
iragen [17]

Given Information:

Magnetic field = B = 1×10⁻³ T

Frequency = f = 72.5 Hz

Diameter of cell = d = 7.60 µm = 7.60×10⁻⁶ m

Required Information:

Maximum Emf = ?

Answer:

Maximum Emf = 20.66×10⁻¹² volts

Explanation:

The maximum emf generated around the perimeter of a cell in a field is given by

Emf = BAωcos(ωt)

Where A is the area, B is the magnetic field and ω is frequency in rad/sec

For maximum emf cos(ωt) = 1

Emf = BAω

Area is given by

A = πr²

A = π(d/2)²

A = π(7.60×10⁻⁶/2)²

A = 45.36×10⁻¹² m²

We know that,

ω = 2πf

ω = 2π(72.5)

ω = 455.53 rad/sec

Finally, the emf is,

Emf = BAω

Emf = 1×10⁻³*45.36×10⁻¹²*455.53

Emf = 20.66×10⁻¹² volts

Therefore, the maximum emf generated around the perimeter of the cell is 20.66×10⁻¹² volts

8 0
2 years ago
A child in a tree house uses a rope attached to a basket to lift a 24 N dog upward through a distance of 4.9 m into the house.
jenyasd209 [6]
<h3>Answer:</h3>

117.6 Joules

<h3>Explanation:</h3>

<u>We are given;</u>

  • Force of the dog is 24 N
  • Distance upward is 4.9 m

We are required to calculate the work done

  • Work done is the product of force and distance
  • That is; Work done = Force × distance
  • It is measured in Joules.

In this case;

Force applied is equivalent to the weight of the dog.

Work done = 24 N × 4.9 m

                  = 117.6 Joules

Hence, the work done in lifting the dog is 117.6 Joules

3 0
3 years ago
I need so much help 50 points!!!!!!<br><br>complete the graph
motikmotik

<u>First Symbol </u>: Cobalt (Co)

Its Group Number - 9

Its Period Number - 4

Its Family Name - Transition Metal

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Its Group Number - 14

Its Period Number - 2

Its Family Name - Semiconductor

<u>Third Symbol</u> : Astatine (At)

Its Group Number - 17

Its Period Number - 6

Its Family Name - Halogen

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Its Group Number - 2

Its Period Number - 3

Its Family Name - Alkaline Earth Metal

<u>Fifth Symbol</u> : Xenon (Xe)

Its Group Number - 18

Its Period Number - 5

Its Family Name - Noble Gas

6 0
2 years ago
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