Question

an earthquake 45 km from a city produces p and s waves that ravel outward at 5000 and 3000 m/s, respectively. once city residents feel the shaking of the p wave, how much time do they have before the s wave arrives?

Answer 1

By the velocity, the interval time after the p wave arrived is 6 seconds.

We need to know about velocity to solve this problem. Velocity can be determined as the distance traveled divided by time interval. It can be written as

v = s / t

where v is velocity, s is distance and t is the time interval.

From the question above, we know that.

vp = 5000 m/s

vs = 3000 m/s

s = 45 km = 45000 m

Determine the time taken by p wave

tp = s / vp

tp = 45000 / 5000

tp = 9 seconds

Determine the time taken by s wave

ts = s / vs

ts = 45000 / 3000

ts = 15 seconds

The time interval after p waves is

interval time = ts - tp

interval time = 15 - 9

interval time = 6 second

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