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Novay_Z [31]
2 years ago
11

an earthquake 45 km from a city produces p and s waves that ravel outward at 5000 and 3000 m/s, respectively. once city resident

s feel the shaking of the p wave, how much time do they have before the s wave arrives?
Physics
1 answer:
OleMash [197]2 years ago
3 0

By the velocity, the interval time after the p wave arrived is 6 seconds.

We need to know about velocity to solve this problem. Velocity can be determined as the distance traveled divided by time interval. It can be written as

v = s / t

where v is velocity, s is distance and t is the time interval.

From the question above, we know that.

vp = 5000 m/s

vs = 3000 m/s

s = 45 km = 45000 m

Determine the time taken by p wave

tp = s / vp

tp = 45000 / 5000

tp = 9 seconds

Determine the time taken by s wave

ts = s / vs

ts = 45000 / 3000

ts = 15 seconds

The time interval after p waves is

interval time = ts - tp

interval time = 15 - 9

interval time = 6 second

Find more on velocity at: brainly.com/question/25749514

#SPJ4

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Which satellite has the greatest gravitational force with Earth?
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A person is hauling their taco stand and it takes 3,500 Joules of work to stop the taco stand. What force was exerted on the tac
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Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.

<h3>What is Work done?</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = f × d

Where f is force applied and d is distance travelled.

Given that;

  • Work done W = 3500J = 3500kgm²/s²
  • Distance covered d = 1.5m
  • Force applied F = ?

W = f × d

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f = 3500kgm²/s² ÷ 1.5m

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Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.

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