Answer:
![T_{2}=278.80 K](https://tex.z-dn.net/?f=T_%7B2%7D%3D278.80%20K%20)
Explanation:
Let's use the equation that relate the temperatures and volumes of an adiabatic process in a ideal gas.
.
Now, let's use the ideal gas equation to the initial and the final state:
![\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}](https://tex.z-dn.net/?f=%5Cfrac%7Bp_%7B1%7D%20V_%7B1%7D%7D%7BT_%7B1%7D%7D%20%3D%20%5Cfrac%7Bp_%7B2%7D%20V_%7B2%7D%7D%7BT_%7B2%7D%7D)
Let's recall that the term nR is a constant. That is why we can match these equations.
We can find a relation between the volumes of the initial and the final state.
![\frac{V_{1}}{V_{2}}=\frac{T_{1}p_{2}}{T_{2}p_{1}}](https://tex.z-dn.net/?f=%20%5Cfrac%7BV_%7B1%7D%7D%7BV_%7B2%7D%7D%3D%5Cfrac%7BT_%7B1%7Dp_%7B2%7D%7D%7BT_%7B2%7Dp_%7B1%7D%7D)
Combining this equation with the first equation we have:
![(\frac{T_{1}p_{2}}{T_{2}p_{1}})^{\gamma -1} = \frac{T_{2}}{T_{1}}](https://tex.z-dn.net/?f=%28%5Cfrac%7BT_%7B1%7Dp_%7B2%7D%7D%7BT_%7B2%7Dp_%7B1%7D%7D%29%5E%7B%5Cgamma%20-1%7D%20%3D%20%5Cfrac%7BT_%7B2%7D%7D%7BT_%7B1%7D%7D)
![(\frac{p_{2}}{p_{1}})^{\gamma -1} = \frac{T_{2}^{\gamma}}{T_{1}^{\gamma}}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bp_%7B2%7D%7D%7Bp_%7B1%7D%7D%29%5E%7B%5Cgamma%20-1%7D%20%3D%20%5Cfrac%7BT_%7B2%7D%5E%7B%5Cgamma%7D%7D%7BT_%7B1%7D%5E%7B%5Cgamma%7D%7D)
Now, we just need to solve this equation for T₂.
![T_{1}\cdot (\frac{p_{2}}{p_{1}})^{\frac{\gamma - 1}{\gamma}} = T_{2}](https://tex.z-dn.net/?f=T_%7B1%7D%5Ccdot%20%28%5Cfrac%7Bp_%7B2%7D%7D%7Bp_%7B1%7D%7D%29%5E%7B%5Cfrac%7B%5Cgamma%20-%201%7D%7B%5Cgamma%7D%7D%20%3D%20T_%7B2%7D%20)
Let's assume the initial temperature and pressure as 25 °C = 298 K and 1 atm = 1.01 * 10⁵ Pa, in a normal conditions.
Here,
Finally, T2 will be:
![T_{2}=278.80 K](https://tex.z-dn.net/?f=T_%7B2%7D%3D278.80%20K%20)
It's very hard to see the self-portrait, so I can't identify him.
Answer:
The answer is "a, c and b"
Explanation:
- Its total block power is equal to the amount of potential energy and kinetic energy.
- Because the original block expansion in all situations will be the same, its potential power in all cases is the same.
- Because the block in the first case has no initial speed, the block has zero film energy.
- For both the second example, it also has the
velocity, but the kinetic energy is higher among the three because its potential and kinetic energy are higher. - While over the last case the kinetic speed is greater and lower than in the first case, the total energy is also higher than the first lower than that of the second.
- The greater the amplitude was its greater the total energy, therefore lower the second, during the first case the higher the amplitude.
Base on your question where a 14.8g of piece of Styrofoam carries a net charge of -0.742C and is suspended in equilibrium above the center of a large, horizontal sheet of plastic so the ask of the problem is to calculate the charge per unit area on the plastic sheet. The answer would be 21.96