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sergeinik [125]
3 years ago
5

This problem is a base conversion problem masquerading as a "word problem". You are responsible for controlling the stage lights

at a small theater. The control box has control switches for 10 separate lights, and each switch can make its corresponding light off, red, green, yellow, or blue. How many different patterns of lighting can you set up?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

The number of different patterns of lighting that can be set up is 9,765,625.

Step-by-step explanation:

The options of each light switch are:

S = {Switch OFF, Red, Green, Yellow and Blue}

There are 5 ways a single light switch can be controlled.

There are 10 separate lights.

Each light has 5 options to operate.

And each light switch is independent of the others,i.e. if one light is red the other can be any of the 5 options.

Then the 10 lights has:

5\times 5\times 5\times 5\times 5\times 5\times 5\times 5\times 5\times 5=5^{10}=9765625

Thus, the number of different patterns of lighting that can be set up is 9,765,625.

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Irina18 [472]

Answer:

4x^{3}

Step-by-step explanation:

<u>Given:</u>

(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}

<u>Apply exponent rule of distribution:</u>

\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}

<u>Simplify the numerator:</u>

\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}

<u>Simplify the denominator:</u>

\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}

<u>Simplify:</u>

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-> To explain this party since it is a bigger jump, 3^{\frac{1}{3}}x is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have x^{3} leftover too.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0
3 years ago
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