Electromagnetic radiation at its maximum wavelength is ____

A galvanic cell with E o cell = 0.30 V can be constructed using an iron electrode in a 1.0 M Fe(NO3)2 solution, and either a tin

Andreyy89

Answer: The half reactions are written below.

Explanation:

Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

We are given a chemical cell which is Fe-Sn cell. The half reaction follows:

Oxidation half reaction: $Fe\rightarrow Fe^{2+}+2e^-;E^o_{Fe^{2+}/Fe}=-0.44V$

Reduction half reaction: $Sn^{2+}+2e^-\rightarrow Sn;E^o_{Sn^{2+}/Sn}=-0.14V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, zinc will always undergo reduction reaction will get reduced.

Total cell reaction: $Fe+Sn^{2+}\rightarrow Fe^{2+}+Sn$

Hence, the half reactions are written above.

3 0

3 years ago

Please help me with this it’s a quiz :(

STatiana [176]

Answer:

Carbon dixoide and water combine to form glucose and oxgen.

I hope this helped! :D

Explanation:

this process by which green plants and some other organisms use sunlight to synthesize foods from carbon dioxide and water. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a byproduct.

4 0

3 years ago

Consider the combustion of octane (C8H18)

Masja [62]

First, you have to find now many moles of octane are present in 191.6g of octane. To do this you need to do this you need to divide 191.6g by its molar mass (which is 114g/mol). This will give you 1.681 moles of octane. Then you need to use the fact that 2 moles of octane are us ed to make 16 moles of carbon dioxide to find how many moles of carbon dioxide 1.681mole of octane produces. To do this you need to multiply 1.681mole by 16/2 to get 13.45mol carbon dioxide. The final step is to find the number of grams presswnt in 13.446 moles of carbon dioxide. To do this you need to multiply 13.446 mole by carbon dioxides molar mass (which is 44g/mol) to get 591.6 g of carbon dioxide.
Therefore, 591.6g of carbon dioxide is produced when 191.6 grams of octane is burned.

I hope this helps. Let me know in the comments if anything is unclear.

8 0

3 years ago

Starting with lead (ii) carbonate describe how a solid sample of lead (ii) sulphate can be prepared

tatuchka [14]

The preparation of lead (ii) sulphate from lead (ii) carbonate occurs in two steps:

insoluble lead carbonate is converted to soluble lead (ii) nitrate
soluble lead (ii) nitrate is reacted with sulphuric acid to produce lead (ii) sulphate.

<h3>How can a solid sample of lead (ii) sulphate be prepared from lead (ii) carbonate?</h3>

Lead (ii) carbonate and lead (ii) sulphate are both insoluble salts of lead.

In order to prepare lead (ii) sulphate, a two step process is performed.

In the first step, Lead (ii) carbonate is reacted with dilute trioxonitrate (v) acid to produce lead (ii) nitrate.

PbCO₃ + 2HNO₃ → Pb(NO₃)₂ + CO₂ + H₂O

In the second step, dilute sulfuric acid is reacted with the lead (ii) nitrate to produce insoluble lead (ii) sulphate which is filtered and dried.

Pb(NO₃)₂ + H₂SO₄ → PbSO₄ + 2HNO₃

In conclusion, lead (ii) sulphate is prepared in two steps.

Learn more about lead (ii) sulphate at: brainly.com/question/188055

#SPJ1

4 0

2 years ago

Which of the mole ratios would be used to set up the below problem?

san4es73 [151]

A.3 moles H2

1 mole N2

I think it is correct

4 0

3 years ago

Electromagnetic radiation at its maximum wavelength is _____.