Mg(s)+2HCl(aq)→MgCl2(aq)+H2(g)
(since the molar mass of Mg is not given, assuming that it's mola mass is 24gmol¯1)
1st find the moles of Mg using the equation n=m/M where
n - moles
m - mass
M - molar mass
Therefore :
n = 0.39375mol
n = 0.39mol
Then using the equation n=V/Vm where;
n = mol
V = volume
Vm = molar volume
Find the volume.
n = V/Vm
(n =0.39mol , Vm = 22.4dm³mol¯¹)
V = 0.39mol×22.4dm³mol¯¹
V = 8.736dm³
Answer:
Explanation:
Hello,
In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:
Clearly, the concentrated solution is 7.00M and the diluted solution is unknown, thus, the concentration of the diluted solution after the dilution to 100 mL is:
Best regards.
Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is 021.65 mole
Mole is the unit of amount of substances of specified elementary entities
According to the ideal gas law he number of moles of a gas n can be calculated knowing the partial pressure of a gas p in a container with a volume V at an absolute temperature T from the equation
n =pV/RT
Here given data is volume = 87.1 liters
Temperature = 74 °C means 347.15 k
Pressure = 3.5 atm
R = 0.0821
Putting this value in ideal gas equation then
n =pV/RT
n = 3.5 atm×87.1 liters / 0.0821 ×347.15 k
n = 021.65 mole
Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is 021.65 mole
Know more about mole of helium
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Answer:
14 mol
Explanation:
CH4(g) + 2O2(g) -------» CO2(g) + 2H2O(g)
from reaction 1 mol 2 mol
given 7 mol x mol
x = (7*2)/1 = 14 mol
