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Andreyy89
2 years ago
13

True or false pls sue tmrps

Chemistry
1 answer:
UNO [17]2 years ago
6 0

Answer:

5. False

Explanation:

Drinking contaminated water causes jaundice

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When considering light moving through a diffraction grating, you should treat the light as what?
liraira [26]

Answer:

A particle

Explanation:

Modern quantum theory holds that light has both wave-like and particle-like properties. When the length scales involved are large compared to the wavelengths of light (ex., forming images with thin lenses), the

particle nature of light dominates.

5 0
3 years ago
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What are the complete Ionic and Net Ionic equations for the following
zhenek [66]

Answer:

Check photo

Explanation:

5 0
3 years ago
K forms the compound K2O , which is an ionic compound that is brittle. Identify another element, M , that is likely to form a br
meriva

The metal is sodium, Na.

<u>Explanation:</u>

K₂O is an ionic compound in which K is in the oxidation state of +1 and it belongs to group 1.

Group 1 elements also form oxides with the metals with the general formula M₂O and M being Na, K, Li and so on.

Metals Like sodium and Potassium are so brittle in nature and also their oxides.

So the other metal that form metal oxide which is brittle as well as ionic in nature, and so the metal oxide is Na₂O.

So the metal is sodium, Na.  

4 0
3 years ago
A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica
Sladkaya [172]

Answer: The empirical formula for the given compound is CH_5N

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

For Hydrogen  = \frac{16.2}{3.23}=5.01\approx 5

For Oxygen  = \frac{3.24}{3.23}=1.00\approx 1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

3 0
3 years ago
Look at the image pls. The question is there
ira [324]

Answer:

Look at the image pls. The question is there

:

4 0
3 years ago
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