Answer:
c. Smaller than.
Explanation:
The energy stored in a capacitor is given as
E = 1/2CV²...................... Equation 1
Where E = Energy stored in a capacitor, C = capacitance of the capacitor, V = Voltage.
Also,
C = εA/d ......................Equation 2
Where ε = permitivity of the material, A = cross-sectional area of the plate, d = distance of separation of the plate.
substitute equation 2 into equation 1
E = 1/2εAV²/d ................. Equation 3
From equation 3 above,
The energy stored in a capacitor is inversely proportional to the distance of separation between the plates.
Hence when the plate is pulled apart by a distance D (D>d) The energy stored in the capacitor will be smaller.
The right option is c. Smaller than.
The change in the total energy of the object is zero (0).
The given parameters:
work done by the machine, W = 50 J
mass of the object, m = 10 kg
To find:
the change in the total energy of the object
The change in the total energy of the object is the difference between the objects initial energy due to its position and the work done on the object.
Based on work energy-theory, the work done on the object is equal to the energy of the object.
- The energy of the object = work-done on the object
- The change in total energy = 50 J - 50 J = 0
Thus, the change in the total energy of the object is zero (0).
Learn more here: brainly.com/question/20377140
Ohm’s law states:
I*R = U
So we just fill in:
U = 11 A * 60 Ω = 660 V
Answer: When a material is heated or cooled, two changes may happen to the particles within the material: Chemical bonds between the particles may form, break or stretch. There is a change in the chemical potential store of energy in the material. The material will heat up or cool down as the particles within it gain or lose speed.
Explanation:
A, something to remember is that if the numbers are even the answer too will be even. Every time hope this helps :>
