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Talja [164]
3 years ago
15

Is Amplitude longitude or transverse

Physics
1 answer:
Elan Coil [88]3 years ago
6 0

Answer:

Amplitudes are present in both transverse and longitidinal waves, all waves actaually.

Explanation:

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Help, please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Alik [6]

Answer:

D

Explanation:

8 0
3 years ago
A 140 g baseball is moving horizontally to the right at 35 mis when it is hit by the bat. the ball fl ies off to the le ft at 55
Anit [1.1K]

Answer:

J = 12.32kg*m/s

Explanation:

Assumptions: I'm assuming mis is m/s

Given: The baseball's mass is 140g, so convert to kg, 0.140kg. (Good rule of thumb, in physics convert grams to kilograms). It is initially traveling 35 m/s to the right.

When it hits the bat, it flies left with a velocity of 55 m/s at an angle of 25°. To reiterate:

mass = 0.140kg, Initial: 35m/s, Final: 55m/s at an angle of 25°

For this problem, we have to use the impulse equation, but before that lets break the velocity into components (It will be apparent towards the end):

The initial velocity is moving only in the horizontal direction, so:

v_{0x} = 35 m/s

The final velocity has an x and a y component:

v_{fx} = 55cos(25) = 49.84692829m/s\\v_{fy} = 55sin(25) = 23.2440044m/s

Now the equation for impulse is (dp is Δp, which is difference in momentum; dv is Δv, the difference in velocity; J is impulse):

J = dp= m*dv

To get Δv, we have to find the difference of velocity, that is why we broke it into components. I'm going to define right as positive and left as negative. After that, we find the velocity vector:

dv_{x} = (35-(-49.84692829)) = 84.84692829 m/s\\dv_{y} = (0-(23.2440044)) = -23.2440044 m/s\\dv = \sqrt{(84.84692829)^2+(-23.2440044)^2} = 87.97320604m/s

Finally, substitute into the equation

J = m*dv\\J = 0.140kg * 87.97320604m/s\\J = 12.31624885kg*m/s\\J = 12.32 kg*m/s

J = 12.32kg*m/s

8 0
3 years ago
A car starts at rest and accelerates at a rate of 4 m/s^2. How far does the car travel in 5
aleksley [76]

Answer:

C. 50m

Explanation:

Given parameters:

Initial velocity  = 0m/s

Acceleration  = 4m/s²

Time of travel  = 5s

Unknown:

distance covered  = ?

Solution:

To solve this problem, we use the expression below;

   S  = ut  + \frac{1}{2} at²  

S is the distance

u is the initial speed

t is the time

a is the acceleration

            S  = (0x 5) + \frac{1}{2} x 4 x 5²   = 50m

6 0
3 years ago
A flywheel of diameter 1.2 m has a constant angular acceleration of 5.0 rad/s2. The tangential acceleration of a point on its ri
Anna71 [15]

Answer:

3 m/s²

Explanation:.

To solve this, we use the formula of tangential acceleration. The tangential acceleration is given by the following equation:

a(t) = r * a(a)

where

a(t) is the tangential acceleration, m/s²

r is the radius, m

a(a) is the angular acceleration, rad/s²

Again, we know that the radius can be gotten by saying r = d/2, thus, r = 1.2/2 = 0.6 m

We then multiply this by the angular acceleration, to get our tangential acceleration

a(t) = 0.6 * 5 = 3 m/s²

Therefore, the Tangential acceleration of a point on the flywheel rim has been found to be 3 m/s²

3 0
3 years ago
PLS ANSWER REAL ANSWERS ONLY
Julli [10]

Answer:

Who is moving the fastest: Green triangle

What is the slope of Blue Diamonds: 5/6 or 5/7, can’t tell completely

<h2><u>Hope This helped!</u></h2>

7 0
3 years ago
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