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mr Goodwill [35]
3 years ago
13

An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 16.0 m if her initial speed is 3.60 m/

s. what is the free-fall acceleration on the planet? (ignore air resistance.)
Physics
1 answer:
Airida [17]3 years ago
7 0
The maximum height that is reached by an object thrown or jumped at a certain initial velocity can be calculated through the equation,

   2ad = Vf² - Vi²

Vf is zero (0) in this equation because this is the point at the velocity at the maximum height of the object.

Substituting the known values,
  2(a)(-16) = 0 - (3.6)²

The value of a from the equation is 0.405 m/s².

<em>Answer: 0.405 m/s²</em>
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You're trying to stop a car that is rolling down-hill. Gravity is pulling it forward with a force of 200 N. If the car has a mas
lara31 [8.8K]

Answer:

no idea .

Explanation:

8 0
3 years ago
In a city grid, each block on the east-west streets is 100 meters long. Each block on the north-south streets is 20 meters long.
alex41 [277]

Answer:

72.1 m

Explanation:

Hello!

When the walker walks west, each block he walks will be of 100 m, so the walker walked 4*100m = 400 m west.

Similarly, when the walker walks south, he walks 20 meters per block, therefore, the walker walked 4*20 m = 80 m south.

Since the directions west and south are perpendicular, the distance between the start ad end point is:

d = √(400^2 + 80^2) m = 407.92 m

However the walker traveled 480 m

Therefore, the walker traveled 480 - 407.9 m = 72.1 m farther than the actual distance

8 0
3 years ago
4) The components of Vector A are given as follows Ax = -2.4 Ay = + 3.8 What is the magnitude of the A, and what is the angle th
Monica [59]

Answer:

A = 4.49

α = 57.72°

Explanation:

Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.

A=\sqrt{A_{x}^{2} +A_{y}^{2} } \\A=\sqrt{(2.4)^{2} +(3.8)^{2} }\\A=4.49

The angle tangent can be used to determine the angle.

tan(\alpha )=\frac{3.8}{2.4}\\tan(\alpha ) =1.5833\\\alpha =tan^{-1}(1.5833) \\\alpha = 57.72 (deg)

5 0
3 years ago
If the work required to stretch a spring 1 ft beyond its natural length is 12 ft-lb, how much work is needed to stretch the same
Angelina_Jolie [31]

Answer:W=\frac{3}{4} ft-lb

Explanation:

Given

Work required to stretch 1 ft is 12 ft-lb

and we have to find work required to stretch 3 in.

i.e. \frac{1}{4} ft

12=\frac{1}{2}K\left ( 1\right )^2 ------(1)

W=\frac{1}{2}k\left ( \frac{1}{4}\right )^2-----(2)

divide (1)&(2)

\frac{12}{W}=\left ( \frac{4}{1}\right )^2

W=\frac{12}{4\times 4}

W=\frac{3}{4} ft-lb

6 0
3 years ago
What does a fossil of an ancient shark in kansas indicate?
sergij07 [2.7K]

The correct answer is:

That the land where it specifically was has been moving and that years ago that place was under water.

Explanation:

Kansas has been the cause of some of the most luxurious fossil findings in US history. The fossil record of Kansas spans from the Cambrian to the Pleistocene. From the Cambrian to the Devonian, Kansas was coated by a shallow sea.

3 0
3 years ago
Read 2 more answers
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