Answer:
v= 4.9 m/s in east direction ( or v=4.9 m/s * i )
Explanation:
Since the passenger moves along the train ( in the north direction relative to the train) then if the train is traveling east relative to the ground , the passenger will also travel to the east relative to the ground .
Then the magnitude of the velocity will be
v= 1.40 m/S + 3.5 m/s = 4.9 m/s
v= 4.9 m/s
and the direction will be east ( if the x axis represents east direction and y-axis the north direction , then the velocity vector will be v=4.9 m/s * i )
Explanation:
In order to compute correctly the sum of the two terms, we have to rewrite one of them such that they have the same exponent.
The two terms are:


For instance, we can re-write the second term such as it also has a power
. In order to do that, we have to move the decimal point one place to the left, therefore:

At this point, the two numbers have the same exponent, so we can just add them together by adding the bases and keeping the same exponent, -2:

The correct answer is B) Ultraviolet light source. Hope this helps.
Answer:
∆ = 14°
Explanation:
Let the angle be ∆
Opposite = 2.07 m/s
Adjacent = 8.3 m/s
Tan ∆ = opposite / adjacent
Tan ∆ = 2.07 / 8.3
Tan ∆ = 0.2494
∆ = ArcTan (0.2494)
∆ = 14°
The angle from vertical the raindrops make for a person jogging is 14°
The conservation of the momentum allows to find the result of how the astronaut can return to the spacecraft is:
- Throwing the thruster away from the ship.
The momentum is defined as the product of the mass and the velocity of the body, for isolated systems the momentum is conserved. If we define the system as consisting of the astronaut and the evo propellant, this system is isolated and the internal forces become zero. Let's find the moment in two moments.
Initial instant. Astronaut and thrust together.
p₀ = 0
Final moment. The astronaut now the thruster in the opposite direction of the ship.
= m v + M v '
where m is propellant mass and M the astronaut mass.
As the moment is preserved.
0 = m v + M v ’
v ’=
We can see that the astronaut's speed is in the opposite direction to the propeller, that is, in the direction of the ship.
The magnitude of the velocity is given by the relationship between the masses.
In conclusion, using the conservation of the momentun we can find the result of how the astronaut can return to the ship is:
- Throwing the thruster away from the ship.
Learn more here: brainly.com/question/14798485