Answer:
The function has at least 1 zero within the interval [-2,5].
Step-by-step explanation:
The intermediate value theorem states that, for a function continuous in a certain interval ![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
, then the function takes any value between 
and 
at some point within that interval.
This theorem has an important consequence:
If a function 
is continuous in an interval [a,b], and the sign of the function changes at the extreme points of the interval:
(or viceversa)
Then the function f(x) has at least one zero within the interval [a,b].
We can apply the theorem to this case. In fact, here we have a function f(x) continuous within the interval
[-2,5]
And we also know that the function changes sign at the extreme points of the interval:
Therefore, the function has at least 1 zero within the interval [-2,5], so there is at least one point x' within this interval such that
When you rotate across the x-axis it will be in quadrant 4 now and then when rotating a point 180 degrees counterclockwise about the origin our point A(x,y) becomes A'(-x,-y). So all you do is make both x and y negative.
hope this helps:))
Idk what is the answers so i see if i got then right
Ok, use the sum of triangle theorm all angles of the triangle has a sum of 180 degrees. B is 90 degrees because it labeled it self ABC the A angle seems by the degree to be at the top of the triangle and there needs to be a 90 degree angle in a right triangle. Now if you add 90 + 28 you get 118 degrees subtract that from the sum of all the angles ( 180 degrees), and get 62 degrees as angle C. Angle A is 28 degrees, angle B is 90 degrees, angle C is 62 degrees.
Answer:
like we were five doeeeee
Step-by-step explanation:
