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snow_lady [41]
3 years ago
15

Help please thanks you

Chemistry
1 answer:
scoundrel [369]3 years ago
5 0

Explanation:

Ok so water is H2O and cabon dioxide in the air is CO2, so the water goes through the carbon dioxide and makes acid rain H2SO4.

Now we have our limestone which is CaCO3.

What happens is that the acid breaks apart our limestone into Ca2+ and CO3 2-. This then reforms into Calcium bicarbonate Ca(CO3)2.

Calcium bicarbonate is soluble in water and is hence washed away by the rain eroding the limestone.

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Ethanol has a Kb of 1.22 °C/m and usually boils at 78.4 °C. How many mol of an nonionizing solute would need to be added to 48.8
Galina-37 [17]

Answer:

0.272 mol

Explanation:

∆Tb = m × Kb

∆Tb = 85.2°C - 78.4°C = 6.8°C

Kb = 1.22°C/m

mass of ethanol = 48.80 g = 48.80/1000 = 0.0488 kg

Let the moles of non-ionizing solute be y

m (molality) = y/0.0488

6.8 = y/0.0488 × 1.22

y = 6.8×0.0488/1.22 = 0.272 mol

6 0
3 years ago
If the copper ion just GAINED electrons,
viva [34]
Reduction is the answer
8 0
3 years ago
Read 2 more answers
What volume of water is produced when 38.5 g of ethanol reacts with oxygen at 500°C at 1.75 atm?
tensa zangetsu [6.8K]

Answer:

90.99 or 91.0

Explanation:

Using the balanced equation, you convert 38.5g of ethanol to moles of water. From there, you plug the values into the Ideal Gas Equation: PV=nRT.

Download pdf
3 0
3 years ago
Read 2 more answers
PLEASE HELP MEEEEE!!!
ololo11 [35]

Answer:

Increasing temperature increases the solubility of most salts, but not all. The reason for the differences is that dissolution involves three steps: breaking bonds of salt in the lattice; forming cavities in water the same size as the ions; interacting the salt with water in the cavity.

7 0
3 years ago
Write the balanced equation for the combustion of isooctane to produce water vapor and carbon dioxide gas.Assuming gasoline is i
tangare [24]

Answer:

The yield is 16 moles of CO2 per 2 moles of isooctane.

The mass of CO2 is 1.15 billion tonnes

Explanation:

First we set the unbalanced equation:

C_{8}H_{18} + O_{2} \longrightarrow CO_{2} + H_{2}O

Now we proceed to balance the equation:

2C_{8}H_{18} + 25O_{2} \longrightarrow 16CO_{2} + 18H_{2}O

With the equation balanced, we see that the theoretical yield is 16 moles of CO2 per 2 moles of isooctane and we can proceed to make calculations with the following data:

\rho _{C_{8}H_{18}}=0.69 g/mL\\Consumption: 142.86x10^{9} gal\\1gal=3785.41 mL\\M_{C_{8}H_{18}}=114.23g/mole\\M_{CO_{2}}=44.01g/mole\\

Knowing the different relations between mass, density and molar mass, we have the following results:

V_{C_{8}H_{18}}=5.41x10^{14}mL\\m_{C_{8}H_{18}}=3.73x10^{14}g\\n_{C_{8}H_{18}}=3.27x10^{12}mole\\n_{CO_{2}}=2.62x10^{13}mole\\m_{CO_{2}}=1.15x1015g\\m_{CO_{2}}=1.15x10^{9}tonnes

8 0
4 years ago
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