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Arada [10]
3 years ago
9

A 5.36 kg object falls freely (ignore air resistance), after being dropped from rest. Determine the initial kinetic energy (in J

), the final kinetic energy (in J), and the change in kinetic energy (in J) for the following.
(a) first meter of fallinitial kinetic energy? Jfinal kinetic energy? Jchange in kinetic energy? J(b) second meter of fallinitial kinetic energy? Jfinal kinetic energy? Jchange in kinetic energy
Physics
1 answer:
matrenka [14]3 years ago
6 0

Answer: 52.53

Explanation:

m*g = 5.36k * 9.8N/kg = 52.53 N. = Wt.

of object.

a. KE = 0 J. = Initial KE

V^2 = Vo^2 + 2g*h

V^2 = 0 + 19.6*1 = 19.6

V = 4.43 m/s.

KE = 0.5m*V^2 = 2.68*4.43^2 = 52.59 J.

b. V^2 = Vo^2 + 2g*h

V^2 = 4.43^2 + 19.6*1 = 39.22

V = 6.26 m/s.

KEo = 2.68*4.43^2 = 52.59 J.

KE = 2.68*6.26^2 = 105 J.

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A proton accelerates from rest in a uniform electric field of 610 N/C. At some later time, its speed is 1.4 106 m/s.(a) Find the
nata0808 [166]

Answer:

a) 5.851× 10¹⁰m/s²

b) 2.411×10⁻¹¹s

c)  1.70×10⁻¹¹m

d) 1.661×10⁻²⁷KJ

Explanation:

A proton in the field experience a downward force of magnitude,

F = eE. The force of gravity on the proton will be negligible compared to the electric force

F = eE

a= eE/m

= 1.602×10⁻¹⁹ × 610/1.67×10⁻²⁷

= 5.851× 10¹⁰m/s²

b)

V = u + at

u= 0

v= 1.4106m/s

v= (0)t + at

t= v/a

= 1.4106m/s/5.851 ×10¹⁰

= 2.411×10⁻¹¹s

c)

S = ut + at²

= (o)t + 5.851×10¹⁰×(2.411×10⁻¹¹)²

= 1.70×10⁻¹¹m

d)

Ke = 1/2mv²

    = (1.67×10⁻²⁷×)(1.4106)²/2

 =  1.661×10⁻²⁷KJ

5 0
3 years ago
Velocity question...is it A B Cor D
Ket [755]
In a constant acceleration of 3m per second, after 10 seconds,

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B. 30m/s is your answer

hope this helps :D
6 0
3 years ago
Read 2 more answers
half life worksheet answer key 3. What percent of a sample As-81 remains un-decayed after 43.2 seconds
Ivahew [28]

The final mass after decay can be obtained by using under given relation:

half life period of As-81 = 33 seconds

mf = mi x (1/2^n)

= 100 x ( 1/2^(43.2/33))

= 40.4 %


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Answer:

Doppler Radar gathers information about precipitation by sending out pulses of ___Radio wave___ energy

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