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Musya8 [376]
3 years ago
12

Time-outs are ineffective because

Physics
2 answers:
maria [59]3 years ago
8 0
I think the correct answer would be the child quietly sits until the timer goes off. It is ineffective because the child would be used to this process and would come to a time where he will not get something from it.Also, it would make a child feel isolated and alone which would affect hi self-esteem in a long run.
Anika [276]3 years ago
6 0

Answer:

Time-outs are ineffective because

c. the child quietly sits until the timer goes off.

Explanation:

Time out was a technique proposed in the early 2000s with a poor notion of behavioralism control of the stimuli or conditions. However, after the children develop resistance to it by understanding that after a short while he or she will be delivered back to what he or she was doing there will be no permanent loss for them. Thus, it is a very ineffective technique created under the seeking of extension of the stimulus. An effective technique of removal of the variable would retrieve the stimuli and explain to the children it was retrieved from him or her because she didn't fulfill the expectations of behavior attached to it.

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Answer:

(a) reaction at each front wheel is 5272N (upward)

(b) force between boulder and pallet is 4124N (compression)

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Acceleration of the truck a_{t = 1 m/s^{2}  (to the left)

when the truck moves 1 m to the left, the boulder is B and pallet A are raised 0.5 m, then,

a_{A} =  0.5 m/s^{2} (upward) , a_{B} =  0.5 m/s^{2} (upward)

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                                  = 2T- (400 + 50)*(9.81 m/s^{2}) = (400 + 50)*(0.5 m/s^{2})

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Truck:  M_{R} = ∑(M_{R})eff: = -N_{f} (3.4m) + m_{T} (2.0m) - T (0.6m)= m_{T} a_{T} (1.0m)

Nf = (2.0m)(2000 kg)(9.81 m/s^{2} )/3.4m -  (0.6 m)(2320 N)/3.4m + (1.0 m)(2000 kg)(1.0 m/s^{2})  = 11541.2N - 409.4N - 588.2N = 10544N

∑fy (upward) = ∑(fy)eff: N_{f} + N_{R} - m_{T}g = 0

                                       10544 + N_{R}  - (2000kg)(9.81 m/s^{2} ) = 0

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   ∑fx (to the left) = ∑(fx)eff:  F_{R} - T = m_{T} a_{T}

                                      F_{R} = 2320N + (2000kg)(9.81 m/s^{2} ) = 4320N

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            N_{B} = (400kg)(9.81 m/s^{2}) + (400kg)(0.5 m/s^{2}) = 4124N (compression)

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