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mina [271]
3 years ago
14

Determine the force between two long parallel wires, that are separated by a dis- tance of 0.1m the wire on the left has a curre

nt of 10A and the one on the right BT has a current of 15A, both going up. 31十131
Physics
1 answer:
valina [46]3 years ago
3 0

Answer:

3 x 10^-4 N/m

Attractive

Explanation:

r = 0.1 m, i1 = 10 A, i2 = 15 A

The force per unit length between two parallel wires is given by

F = \frac{\mu _{0}}{4\pi }\times \frac{2i_{1}i_{2}}{r}

F = \frac{10^{-7}\times 2\times 10\times 15}{0.1}

F = 3 x 10^-4 N/m

Thus, the force per unit length between two wires is 3 x 10^-4 N/m, the force is attractive in nature because the direction of flow of current in both the wires is same.

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Answer:

So the force of attraction between the two objects is 3.3365*10^-6

Explanation:

m1=10kg

m2=50kg

d=10cm=0.1m

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We have to find the force of attraction between them

F=Gm1m2/d^2

F=6.673*10^-11*10*50/0.1^2

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