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Misha Larkins [42]
3 years ago
6

Please help asap! I have no idea what to write! :) Thanks a bunch!!

Chemistry
1 answer:
Finger [1]3 years ago
3 0

Answer:

I don't know

Explanation:

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the actual yield of a product in a reaction was measured as 2.80 g. if the theoretical yield of the product for the reaction is
olga_2 [115]

The percentage yield of the product if the actual yield was measured as 2.80 g and the theoretical yield is measured as 3.12 g is 11.43%.

<h3>How to calculate percentage yield?</h3>

The percentage yield of a substance can be calculated by dividing the difference between the actual and theoretical yield by the actual yield, then multiplied by 100.

Percentage yield = (theoretical yield - actual yield)/actual yield × 100

According to this question, the actual yield of a product in a reaction was measured as 2.80 and the theoretical yield of the product for the reaction is 3.12 g.

Percent yield = (3.12g - 2.80g)/2.80 × 100

Percent yield = 11.43%.

Therefore, percentage yield of the product if the actual yield was measured as 2.80 g and the theoretical yield is measured as 3.12 g is 11.43%.

Learn more about percent yield at: brainly.com/question/17042787

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5 0
2 years ago
the reaction of 50 mL of gas with 50 mL of gas via the equation: Cl2(g) + C2H4(g) ➔ C2H4Cl2 (g) will produce a total of ________
spin [16.1K]

Explanation:

The given data is as follows.

      50 ml of Cl_{2},       50 ml of C_{2}H_{4}

And, it is known that at STP 1 mole of a gas occupies 22.4 L. Hence, moles present in 50 ml of gas are as follows.

          \frac{50}{22.4 \times 1000}      (As 1 L = 1000 ml)

          = 2.23 \times 10^{-3} moles

So, according to the given equation 2.23 \times 10^{-3} moles of Cl_{2} reacts with 2.23 \times 10^{-3} moles of C_{2}H_{4}.

Hence, moles of C_{2}H_{4}Cl_{2} is equal to the moles of C_{2}H_{4} and Cl_{2}.

Therefore, moles of C_{2}H_{4}Cl_{2} = 2.23 \times 10^{-3} moles

           1 mole of C_{2}H_{4}Cl_{2} = 22.4 L

   2.23 \times 10^{-3} moles = 22.4 \times 2.23 \times 10^{-3} moles        

                                = 50 ml of product

Thus, we can conclude that 50 ml of products if pressure and temperature are kept constant.

5 0
4 years ago
Suppose a 20.0 g gold bar at 35.0°C absorbs 70.0 calories of heat energy. Given that the specific heat of gold is 0.0310 cal/g °
timofeeve [1]

We know, change in temperature is given by :

T_2-T_1=\dfrac{q}{mC_p(Gold)}

Putting all given values, we get :

T_2-T_1=\dfrac{70\ cal}{20\ g\times 0.0310\ cal/g^o\ C}\\\\T_2-T_1=112.90^oC\\\\T_2-35^oC=112.90^oC\\\\T_2=(112.90+35)^oC\\\\T_2=147.9^oC

Hence, this is the required solution.

6 0
4 years ago
What must happen for water to boil at a given pressure?
Mademuasel [1]

Answer:

B. The water must gain thermal energy from its surroundings.

Explanation:

Boiling is the process whereby a substance is changed from a liquid state to a gaseous state due to the application of heat. For boiling to be achieved, a liquid substance must reach or exceed its boiling point, which is the specific temperature at which a specific liquid boils.

For this change of state i.e. from liquid to gas, to occur, atoms or molecules of the liquid must gain kinetic energy and move faster. However, this kinetic energy cannot be attained without a rise in temperature, which causes the molecules to gain THERMAL ENERGY or heat energy and move fast. Thermal energy is the energy that arises from a hot substance.

Therefore, for water to boil at a given pressure, it must gain thermal energy from its external surroundings, which causes its molecules to have an increased kinetic energy and move faster. This fast movement of the molecules causes the transition of phases (from liquid to gas).

7 0
3 years ago
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Please helppppppppppppppppppppppp
Lera25 [3.4K]

Answer:

maybe the 3rd stance if your not sure try to search in googel

5 0
3 years ago
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