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frosja888 [35]
2 years ago
15

Question 7(Multiple Choice Worth 4 points)

Physics
2 answers:
vazorg [7]2 years ago
7 0
<h3>Question :</h3>

Which of the following substances is formed during photosynthesis?

⠀ ⠀A. Carbon dioxide

⠀ ⠀B. Light

⠀ ⠀C. Sugar

⠀ ⠀D. Water

<h3>Answer :</h3>

Sugar is formed during photosynthesis.

So, correct option is C. Sugar.

<h3>Explanation :</h3>

During photosynthesis, Carbon dioxide and water are used to produce sugar with help of light.

Nimfa-mama [501]2 years ago
3 0
C is the correct answer, as the equation for photosynthesis is carbon dioxide +water=glucose(sugar) + oxygen
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A football player throws and accelerates a ball (m = 0.150 kg) from rest to a velocity of 50 m/s in 0.0121 sec. Determine the ac
Rasek [7]

Answer:

Acceleration=4m/s²

Force applied =619.8N

Explanation:

Using equation of motion

V=u+at we have: u=o, v=50m/s

50= 0 + a×0.0121

a = 50/0.0121

a= 4m/s²

Neglecting resistance forces

F= ma, where a = v-u/t

F=m×(v-u)/t

F= 0.150 ×(50-0)/0.0121

F=7.5/0.0121

F= 619.8N

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2 years ago
Energy that is transferred from a warmer object to a cooler object is called
alukav5142 [94]

Answer:

Heat

Explanation:

Energy that is transferred from a warmer object to a cooler object is called heat.

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2 years ago
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2 years ago
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A hot air balloon is traveling vertically upward at a constant speed of 4.5 m/s. When it is 28 m above the ground, a package is
ella [17]

Answer:

1.97 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow 21=4.5t+\frac{1}{2}\times -9.8\times t^2\\\Rightarrow 21=-4.5t-4.9t^2\\\Rightarrow 4.9t^2+4.5t-28=0\\\Rightarrow 49t^2+45t-280=0

Solving the above equation we get

t=\frac{-45+\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}, \frac{-45-\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}\\\Rightarrow t=1.97, -2.89

So, the time the package was in the air is 1.97 seconds

3 0
3 years ago
A 2.00 kg box slides on a rough, horizontal surface, hits a spring with a speed of 1.90 m/s and compresses it a distance of 10.0
oksian1 [2.3K]

Answer:

Explanation:

Given

mass of box m=2\ kg

speed of box v=1.9\ m/s

distance moved by the box x=10\ cm

coefficient of kinetic friction \mu _k=0.66

Friction  force f_r=\mu_kN

f_r=0.66\times mg

f_r=0.66\times 2\times 9.8=12.936 \N

Kinetic Energy of box will be utilize to overcome friction and rest is stored in spring in the form of elastic potential energy

\frac{1}{2}mv^2=f_r\cdot x+\frac{1}{2}kx^2

\frac{1}{2}\times 2\times 1.9^2=12.936\times 0.1+\frac{1}{2}\times k\times (0.1)^2

3.61-1.2936=0.005\times k

k=463.28\ N/m

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3 years ago
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