Answer:
The only difference between a planet and a dwarf planet is the area surrounding each celestial body. A dwarf planet has not cleared the area around its orbit, while a planet has.
Explanation:
the three criteria of the IAU for a full-sized planet are: It is in orbit around the Sun. It has sufficient mass to assume hydrostatic equilibrium (a nearly round shape). It has "cleared the neighborhood" around its orbit .
Answer:
(a) 42 N
(b)36.7 N
Explanation:
Nomenclature
F= force test line (N)
W : fish weight (N)
Problem development
(a) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled in at constant speed
We apply Newton's first law of equlibrio because the system moves at constant speed:
∑Fy =0
F-W= 0
42N -W =0
W = 42N
(b) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled with an acceleration whose magnitude is 1.41 m/s²
We apply Newton's second law because the system moves at constant acceleration:
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
∑Fy =m*a
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
F-W= ( W/9.8 )*a
42-W= ( W/9.8 )*1.41
42= W+0.1439W
42=1.1439W
W= 42/1.1439
W= 36.7 N
Answer:
C
Explanation:
BECAUSE ITS GOING ON AND ON IF ITS NOT CORRECT I WILL VOTE YOU BRAINLEST ON MY QUESTION
Answer:
the final speed of the smaller car is 5.624 m/s
Explanation:
Given;
mass of the small car, m₁ = 200 kg
initial velocity of the small car, u₁ = 3 m/s
mass of the larger car, m₂ = 392 kg
initial velocity of the larger car, u₂ = 6 m/s
final velocity of the larger car, v₂ = 1.6 m/s
let the direction of the larger car be positive
let the direction of the smaller car be negative
Apply the principle of conservation of linear momentum to determine the final speed of the smaller car.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
200(-3) + 392(6) = 200v₁ + 392 x 1.6
-600 + 2352 = 200v₁ + 627.2
1752 = 200v₁ + 627.2
1752 - 627.2 = 200v₁
1124.8 = 200v₁
v₁ = 1124.8/200
v₁ = 5.624 m/s
Therefore, the final speed of the smaller car is 5.624 m/s
Answer:
<em>The object-Earth system is open</em>
Explanation:
<u>Accelerated Motion
</u>
When an object is released in free air (with no other forces than the gravity), it describes a free-fall motion and the formulas include the acceleration of gravity as part of the calculations. But when there is another external force, then the acceleration is not the gravity, but the result of the net force exerted on the mass of the object.
By definition, an open system includes the exchange of energy from and to the surroundings, that is why all systems surrounding our planet are considered as open systems. In our case, the object is interacting with the planet's gravity and there is some other external force, which will be computed later. The object-Earth system is open.
If the object starts from rest, its initial speed is zero, and
where a is the acceleration and t is the time. The distance traveled is given by
:
From the two above equations, we find that:
Solving for a
It means the net force is
The object's weight is
This means there is some external force acting upwards delaying the object's fall of a magnitude of
