Answer:

The Andromeda is a galaxy which is nearest to the milky way. It is also named as Messier 31 or M31 or NGC 224. It is a spiral galaxy located at a distance of approximately 2.5 million light years from earth.
another name Andromeda in Hindi is Vaikunth.
The total amount of energy transferred as heat is equal to 288 Joules.
<u>Given the following data:</u>
- Internal energy = 123 Joules
To calculate the total amount of energy transferred as heat, we would apply the first law of thermodynamics.
<h3>The first law of thermodynamics.</h3>
Mathematically, the first law of thermodynamics is given by the formula:

<u>Where;</u>
is the change in internal energy.
- Q is the quantity of heat transferred.
Substituting the given parameters into the formula, we have;

Q = 288 Joules.
Read more on internal energy here: brainly.com/question/25737117
Answer:
1.2kV
Explanation:
We are given that
Linear charge density,



We have to find the potential difference between poinst 5.0 m and 6.0 m from the wire.
We know that potential difference of wire

Where

Substitute the values



1kV=1000 V