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soldier1979 [14.2K]
2 years ago
11

Pedro uses a bar magnet to pick up a nail. He then touches the tip of the nail to some staples.

Physics
2 answers:
scoundrel [369]2 years ago
7 0
This isn’t a question
allochka39001 [22]2 years ago
7 0

Answer:

B) The nail has become a temporary magnet, while the bar magnet remains a permanent magnet.

Explanation:

I hope this helped you ;)

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Two out-of-tune flutes play the same note. One produces a tone that has a frequency of 248 Hz, while the other produces 288 Hz.
zaharov [31]

Answer:

F = 268 Hz

Explanation:

The beat frequency is given as:

Beat Frequency = |Frequency 1 - Frequency 2|\\|

So, for the first flute and tuning fork:

20 Hz = |248 Hz - F|

where,

F = Frequency of tuning fork

F = 248 Hz ± 20 Hz

F = 268 Hz (OR) 228 Hz

Now, for the second flute and tuning fork:

20 Hz = |288 Hz - F|

where,

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F = 268 Hz (OR) 308 Hz

Since, 268 Hz is common from both calculations. Therefore, it will be the frequency of the tuning fork.

<u>F = 268 Hz</u>

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