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stepladder [879]

3 years ago

11

A 422N block is sitting on a frictionless surface and is connected by a massless, extension-less rope over a frictionless pulley

to a 185N mass. What is the acceleration of the blocks and the tension in the cable.

1 answer:

DochEvi [55]3 years ago

6 0

solution is written in attached image.

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Which electromagnetic waves have the shortest wavelength and the highest frequency? _________ waves

Ivan

Answer:

Gamma waves

Explanation:

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3 years ago

Read 2 more answers

Why would you expect the speed of light to be slightly less in the atmosphere then in a vacuum?

azamat

The speed of light to be slightly less in atmosphere then in vacuum because of absorption and re-emission of light by the atmospheric molecules occurred when light travels through a material

<u>Explanation:</u>

When light passes through atmosphere, it interacts or transmits through the transparent molecules in atmosphere. In this process of transmission through atmosphere, the light will be getting absorbed by them and some will get re-emitted or refracted depending upon wavelength.

But in vacuum the absence of any kind of particles will lead to no interaction and no energy loss, thus the speed of the light will be same in vacuum while due to interactions with molecules of atmosphere, there speed will be slightly less compared to in vacuum.

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3 years ago

A 50 kg object traveling at 100 m/s collides (perfectly elastic) with a 50 kg object initially at rest.

tino4ka555 [31]

Answer:

a

Explanation:

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3 years ago

The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.17 Hz, and the acc

aksik [14]

Answer:

d = 8.4 cm

Explanation:

In order to calculate the amplitude of oscillation of the top of the building, you use the following formula for the max acceleration of as simple harmonic motion:

$a_{max}=A\omega^2$ (1)

A: amplitude of the oscillation

w: angular speed of the oscillation = 2 $\pi$ f

f: frequency = 0.17Hz

The maximum acceleration of the top of the building is a 2.0% of the free-fall acceleration. Then, you have:

$a_{max}=0.02(9.8m/s^2)=0.196\frac{m}{s^2}$

Then, you solve for A in the equation (1) and replace the values of the parameters:

$A=\frac{a_{max}}{\omega^2}=\frac{a_{max}}{4\p^2i f^2}\\\\A=\frac{0.196m/s^2}{16\pi^2(0.17Hz)^2}\\\\A=0.042m=4.2cm$

The total distance, side to side, of the oscilation of the top of the building is twice the amplitude A. Then you obtain:

d = 2A = 2(4.2cm) = 8.4cm

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3 years ago

A solution which has a solid solute is saturated at 25°C. It is then heated to 35°C. There is no change in the appearance of the

vampirchik [111]

Answer:

C. oversaturated

Explanation:

Sana nakatulong

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3 years ago