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stepladder [879]
3 years ago
11

A 422N block is sitting on a frictionless surface and is connected by a massless, extension-less rope over a frictionless pulley

to a 185N mass. What is the acceleration of the blocks and the tension in the cable.

Physics
1 answer:
DochEvi [55]3 years ago
6 0

solution is written in attached image.

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poor diet andlack of exersise

Explanation:

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The size of the Milky Way is determined from studying_______
Gemiola [76]

Answer:

expansions

i think

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5 0
3 years ago
An automobile which set the world record for acceleration increase speed from rest to 96 km/h in 3.07 seconds what distance trav
Vesnalui [34]

Answer:

41.02m

Explanation:

Given parameters:

Initial velocity = 0m/s

Final velocity  = 96km/hr

Time taken  = 3.07s

Unknown:

Distance traveled by the time the final speed was achieved = ?

Solution:

To solve this problem, we first find the acceleration of the car;

     Acceleration  = \frac{v - u }{t}

v is the final velocity

u is the initial velocity

t is the time taken

  Now convert the the final velocity to m/s;

          96km/hr to m/s;

               1 km/hr  = 0.278m/s

               96km/hr  = 96 x 0.278 = 26.7m/s

Now;

 Acceleration  = \frac{26.7 - 0}{3.07}   = 8.69m/s²

So;

   v²  = u²  + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

             26.7²  = 0²  + 2 x 8.69 x s

             712.89  = 17.38s

                  s  = 41.02m

3 0
2 years ago
you can use a torque feeler that consists of a meterstick held at the 0 cm end with a weight dangling from various positions alo
Deffense [45]

Answer:

T=7.3575\ N.m

Explanation:

Given:

length of the stick, l=100\ cm=1\ m

position of holding the stick that acts as a hinge, f=0\ cm

mass of the object, m=1\ kg

position of hanging the mass on the meter stick, x=50\ cm=0.5\ m

new position of hanging the mass, x'=75\ cm=0.75\ m

<u>Now the torque in the initial position:</u>

T=mg.x

where:

g= acceleration due to gravity

T=1\times 9.81\times 0.5

T=4.905\ N.m

Now when the mass is at the new position:

T=mg.x'

T=1\times 9.81\times 0.75

T=7.3575\ N.m

7 0
3 years ago
PLEASE HELP THIS IS URGENT!!!!! 50 POINTS!!!
Alja [10]
What math class are you in I think I can help
6 0
3 years ago
Read 2 more answers
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