Answer:
Explanation:
Given data
Distance d=7.00 ft= 7*(1/3.281) =2.1336m
Initial velocity vi=0m/s
To find
Final velocity
Solution
From Kinematic equation we know that:
An object travels 5m/s in 2 seconds. How far did it travel?
2 answers:
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Answer: V = 504m/a
F = 4N
Explanation: please find the attached file for the solution
Answer:
K.E₂ = mg(h - 2R)
Explanation:
The diagram of the car at the top of the loop is given below. Considering the initial position of the car and the final position as the top of the loop. We apply law of conservation of energy:
K.E₁ + P.E₁ = K.E₂ + P.E₂
where,
K.E₁ = Initial Kinetic Energy = (1/2)mv² = (1/2)m(0 m/s)² = 0 (car initially at rest)
P.E₁ = Initial Potential Energy = mgh
K.E₂ = Final Kinetic Energy at the top of the loop = ?
P.E₂ = Final Potential Energy = mg(2R) (since, the height at top of loop is 2R)
Therefore,
0 + mgh = K.E₂ + mg(2R)
<u>K.E₂ = mg(h - 2R)</u>
Answer:
Explanation:
The speed of light is given by
and
hence
Speed of light is given by