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1 year ago

An object travels 5m/s in 2 seconds. How far did it travel?

Physics

2 answers:

gtnhenbr [62]1 year ago

6 0

Answer:

Explanation:

because half I think is the answer

s2008m [1.1K]1 year ago

5 0

Answer:

10 m

Explanation:

5 m/s * 2 s = 10 meters ( see how the ' s ' cancels out?)

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The electric field strength E is measured as:

soldi70 [24.7K]

The correct answer is
<span>force per unit charge.

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span> $E= \frac{F}{q}$
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.

4 0

3 years ago

find the rate of positive acceleration of an automobile which went from a complete stop to a velocity of 30 meters per second in

maks197457 [2]

Answer:

3 m/s^2

Explanation:

acceleration= Change in velocity/time

= 30-0 / 10

= 30/10

=3 m/s^2

3 0

3 years ago

why do a circulatory system is important in meeting the needs of all cells throughout an animals body

valentinak56 [21]

The circulatory system is important in meeting the needs of all cells in the body because it offers means of transport by which cells obtain the materials needed to live and function. The functions of the circulatory system by which the cells are supported include: 1. Respiration- oxygen is delivered to the cells and carbon dioxide is removed from them. 2. Nutrition- nutrients for energy are supplied to every cell in the body. 3. Waste removal- metabolic waste products are taken away before they accumulate and become harmful to the cells. 4. Cellular communication- hormones are transported to the cells and organs that need them for proper functioning. 5.Thermoregulation- As blood circulates, it keeps body temperature balanced and thus cells are able to carry out processes well.

3 0

3 years ago

The weightlifter's internal store of energy decreased when he lifted the bar.

Mumz [18]

Answer:

The energy returns to the weightlifter's muscles, where it is dissipated as heat.

Explanation:

The energy returns to the weightlifter's muscles, where it is dissipated as heat. As long as the weightlifter controls the weight's descent, their muscles are acting as an overdamped shock absorber, as if the weight were sitting on a piston containing very thick fluid, slowly compressing it downward (and slightly heating up the fluid in the process). Since muscles are complicated biological systems and not simple pistons, they require metabolic energy to maintain tension throughout the controlled descent, so the weightlifter feels like they're putting energy into the weight, even though the weight's gravitational potential energy is being converted into heat within the lifter's muscles.

5 0

3 years ago

A positively charged particle is in the center of a parallel-plate capacitor that has charge ±Q on its plates. SUppose the dista

slamgirl [31]

Answer:

Stay the same

Explanation:

First of all, let's find how the capacitance of the capacitor changes.

Initially, it is given by

$C=\frac{\epsilon_0 A}{d}$

where

$\epsilon_0$ is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

From the formula, we see that the capacitance is inversely proportional to the separation between the plates. In this problem, the distance between the plates is doubled, so the capacitance will be halved:

$C' = \frac{1}{2}C$

The potential difference across the capacitor is given by

$V= \frac{Q}{C}$

where

Q is the charge on the plates

C is the capacitance

We see that the voltage is inversely proportional to the capacitance. We said that the capacitance has halved: therefore, the potential difference across the two plates will double:

$V' = 2 V$

Now we can analyze the electric field between the plates of the capacitor, which is given by

$E=\frac{V}{d}$

we said that:

- The voltage has doubled: V' = 2 V

- The distance between the plates has doubled: d' = 2 d

therefore, the new electric field will be

$E'=\frac{2V}{2d}=\frac{V}{d}=E$

So, the electric field is unchanged. And since the force on the particle at the center is directly proportional to the electric field:

F = qE

Then the force on the particle will stay the same.

4 0

3 years ago

An object travels 5m/s in 2 seconds. How far did it travel?​

An object travels 5m/s in 2 seconds. How far did it travel?