Answer:
5 .07 s .
Explanation:
The child will move on a circle of radius r
r = 1.5 m
Let the velocity of rotation = v
radial acceleration = v² / r
v² / r = 2.3
v² = 2.3 r = 2.3 x 1.5
= 3.45
v = 1.857 m /s
Time of revolution = 2π r / v
= 2 x 3.14 x 1.5 / 1.857
= 5 .07 s .
Answer:
2.846m
Explanation:
The diver is performing projectile motion.
To find x(final), we are going to use the equation x(final) = v(initial)*t + x(initial)
x(initial) = 0
x(final) = ?
v(initial) = 2.3 m/s
we don't know t
To find t we will use y(final) = 1/2*(-9.8)*t^2 + v(initial in the y dir.)*t + y(initial)
- 9.8 in the acceleration in the y dir.
y(final) = 0
y(initial) = 7.5
v(initial in the y dir.) = 0
If we solve for t we get: t = 1.237s
Now we have all the components to solve for x(final) in x(final) = v(initial)*t + x(initial)
x(final) = 2.3*1.237 + 0
x(final) = 2.846m
Hello. The answer, though I don't know what options you need to be answered, is that there is less friction between the car tires and the ice, than when they are on the road. Causing the car to slide.
