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ollegr [7]
4 years ago
5

Determine the precent composition of the following compounds:

Chemistry
1 answer:
zmey [24]4 years ago
8 0

Answer: I think the correct answer is B

Explanation:

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How many orbitals does the s subshell contain?
bearhunter [10]

There is only one orbital in the s sublevel. It can hold up to two electrons.

5 0
3 years ago
The bond between carbon and hydrogen is one of the most important types of bonds in chemistry. The length of an H—C bond is appr
nata0808 [166]

Answer:

The dipole moment of H-C bond will be smaller than that of an H-I bond.

Explanation:

The electronegativity of iodine is greater than that of hydrogen.As a result the iodine atom tends to attract the bond electron pair of H-I bond towards itself creating a bond dipole which does not occur in case of H-C bond as the electronegativity of carbon and hydrogen are almost same.

   That"s why dipole moment of H-C bond is smaller than that of H-I bond.

7 0
3 years ago
What is the correct name
Inessa05 [86]

Answer:

The Answer is 2-methylpentane

Or the third one down.

Explanation:

5 0
3 years ago
Read 2 more answers
A student is given an antacid tablet that weighed 5.6832 g. The tablet was crushed and 4.3628 g of he antacid was added to 200 m
SSSSS [86.1K]

Answer:

a) 8.33 ml of the original stomach acid is neutralized

b) 191.67 ml of the stomach acid was neutralized

c)  249.68 ml acid would be neutralized by the original tablet

Explanation:

a) how much of the stomach acid had been neutralized in the 25 mL sample wich was titrated?

25.5 ml of a NaOH solution is equivalent to 25.00 ml of the original stomach acid

8.5 ml NaOH * (25.00 ml original stomach acid / 25.5 ml NaOH) = 8.33 ml original stomach acid

b) how much stomach acid was neutralized y the 4.3628 g tablet?

It takes 8.5 ml NaOH to neutralize 8.33 ml original acid (this is the answer for question 1)

This means the antacid neutralized = 200 ml - 8.33 ml = 191.67 ml

c) how much stomach acid would have been neutralized by the original 5.6832 g tablet

4.3628 g antacid is equivalent to 191.67 ml acid  ( this is the answer for question 2)

5.6832g antacid * (191.67 ml acid / 4.3628 g antacid) = 249.68 ml acid

3 0
3 years ago
Read 2 more answers
A gas is contained in a 5.0-liter container at a pressure of 100 kPa. what size container would be required to contain the gas a
vagabundo [1.1K]
Boyle's law gives the relationship between pressure of a gas and volume of gas.
It states that at constant temperature, pressure of gas is inversely proportional to volume of gas.PV = k 
where P - pressure  V- volume and k - constant 
P1V1 = P2V2 
since the gas occupies the volume of the container, volume of gas is taken as volume of container.
100kPa x 5.0 L = 50 kPa x V
V = 10.0 L 
Answer is C.
4 0
3 years ago
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